Chemistry 12
Santa Monica College
Determination of Kc for a Complex Ion Formation
Objectives
• • Find the value of the equilibrium constant for formation of FeSCN2+ by using the visible light absorption of the complex ion. Confirm the stoichiometry of the reaction.
Background
In the study of chemical reactions, chemistry students first study reactions that go to completion. Inherent in these familiar problems—such as calculation of theoretical yield, limiting reactant, and percent yield—is the assumption that the reaction can consume all of one or more reactants to produce products. In fact, most reactions do not behave this way. Instead, reactions reach a state where, after mixing the reactants, a stable mixture of reactants
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These values can be determined from a reaction table ('ICE' table), as shown in Table 1:
Table 1: Reaction ICE Table Fe3+(aq) Initial Concentration Change in Concentration Equilibrium Concentration [Fe3+]i –x [Fe ]i – x
3+
+
SCN–(aq) [SCN–]i –x [SCN ]i – x
–
!
FeSCN2+(aq) 0 +x x = [FeSCN2+]
The reaction "ICE" table demonstrates the method used in order to find the equilibrium concentrations of each species. The values that come directly from the experimental procedure are found in the shaded regions. From these values, the remainder of the table can be completed.
The initial concentrations of the reactants in Table 1—that is, [Fe3+] and [SCN–] prior to any reaction—can be found by a dilution calculation based on the values from Table 2 found in the procedure. Once the reaction reaches equilibrium, we assume that the reaction has shifted forward by an amount, x. Notice from Table 1 that the value of x is simply equal to the equilibrium concentration of FeSCN2+(aq), or that x = [FeSCN2+] at equilibrium. The equilibrium value of [FeSCN2+] is determined spectroscopically using Beer’s Law. Its initial value in the table is zero because no FeSCN2+(aq) is added to the initial solution. Finally, the equilibrium concentrations of the reactants, Fe3+(aq) and SCN–(aq), are found by subtracting the equilibrium concentration of FeSCN2+(aq) from the initial concentrations of Fe3+(aq) and SCN–(aq), as shown in the table above. Once all the equilibrium values are
Theoretical Yield: The amount of the product obtained when all of the limiting reagent react.
3. Find the number of atoms of each of the substances involved in the reaction.
The freezing point constant (Kf) of water is 1.86 °C m-1. Each mass amount and Van’t Hoff factor was calculated then analyzed in a table.
Part 1: Obtain some 0.200M Fe(NO3)3 solution and some 0.00020M KSCN solution. Starting from the first solution, pour and mix 8.0mL of Fe(NO3)3 solution and 2.0mL of KSCN solution into a test tube, where as the second solution has 7.0mL of Fe(NO3)3 solution and 3.0mL of KSCN solution. Continue this process until 5 test tubes have been filled. Pour
The purpose of this experiment is to study ionic reactions, to be able to write balanced equations, and to be able to write net ionic equations for precipitation reactions.
2) Adding OH⁻ would react with the Fe³⁺ in the system to form a precipitate Fe(OH)₃. This would decrease the [Fe³⁺] in the system. Equilibrium will shift left to counteract the change and the solution becomes lighter yellow in colour.
To study the nature of ionic reactions, write balanced equations, and write net ionic equations for precipitation reactions.
Table 2: Addition of KSCN, Fe(NO₃)₃and Na₂HPO₄to Iron (III) Thiocyanate and Change of Direction of Equilibrium
The excel shows the enthalpy change for some important stream. The reference temperature is 20 degrees. Also the excel show specific heat capacity for some properties such as ice, water, and CH3COONa (4180J/kg.k 996J/kg.k 1229J/kg.k). Stream 4 in Reagent A and Stream 10 show the mass fraction, mass flow, average heat capacity, temperature, reference temperature and the enthalpy for the properties in Reagent A and B.
Consequently, these observations have proven the theory correct that there is a relationship between reactant and product because the mass of the product was very much dependent and affected by the starting material of a reagent that was varied. Figure 1.1 shows that the Calcium chloride was the limiting reagent while it was increasing on the first slope (y=0.3051x-0.0413), but then the Sodium carbonate became the limiting reagent when the Calcium chloride leveled off in the second slope (y=0.0864x+0.082). The mass of product found in the fourth vial in Figure 1.1 drops below the mass of product in the third vial because of a human error that consisted of not letting the powder dry long enough on top of the filter paper and cumulating the powder with a metal scoop too early. Another human error in the experiment consisted of not being very accurate and allowing any of the powder to come of the metal scoop or fall onto the lab table. Moreover, this human error could be the result of an experimental error of using a metal scoop that was bigger than the small vial.
It is suspected that the freezing point is 64.1oC. Due to the short temperature plateau, It is difficult to determine if the freezing point occurs at during the interval (6:00-6:10). However, it appears to be have been the most reasonable determination for freezing point in comparison to the rest of the plot.
formula Kw[Fex(C2O4)y]·zH2O. The variables x, y, and z were determined through the duration of the
Chemical reactions hardly ever complete at a definite end point. Instead, they reach a state of equilibrium at a given temperature where the rate of the forward reaction equals the rate of the reverse reaction. This point of equilibrium is known as the Keq value and can be defined as the ratio of the concentration of products to the concentration of reactants at equilibrium. The value of the equilibrium constant also suggests whether the equilibrium favors the products or reactants. A Keq value larger than one means that the equation favors the products, whereas a Keq value smaller than one signals that the reaction favors the reactants in the reaction. Furthermore, the equilibrium constant is unique in that it should remain the same even with
3. Calculate the total heat released in each reaction, assuming that the specific heat of the solution is the same as for pure water (4.18J/gK). Use q=mcΔT. Show work here and record your answer in Data Table 2.
Kinetics of chemical reactions is how fast a reaction occurs and determining how the presence of reactants affects reaction rates. In this experiment the rate of reaction for Fe+3 and I- is determined. Because the rate of chemical reactions relates directly to concentration of reactants, the rate law is used to find the rate constant, and calculated with specified temperatures.