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Chemistry Ia Ib

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IB
KYAW WAI IB1I
KYAW WAI IB1I
CHEMISTRY IA (2)
TITRATION OF ACID & ALKALI
Name: KYAW WAI
Date: 5th February 2013

IA CRITERIA ASSESSED: DCP, MS

Declaration
I declare that this report I have submitted is my own original work and I have acknowledged the use of words or ideas of another person.

Signature: ______________________________
Marks: ______________________________

Aim of the experiment:
The aim is to determine the water of crystallization of a diprotic acid by titration against a base.

Background:
Many substances that we use are either acidic or basic. Because acids and bases can neutralize each other, that gives us a strategy for finding the unknown concentration of an acid or base when we react …show more content…

Tabulate the results in a neat tabular column.
Data Collection:
(a) Qualitative Data:

Materials | Color/Observations | 1) Sodium Hydroxide | Colorless liquid | 2) Sodium Hydroxide after two drops of phenolphthalein | Pink to colorless liquid | 3) After titration with {(COOH)2.xH2O} | Change from black to colorless liquid |
Table 1:Observation

(b) Quantitative Data: Trials | Amount of NaOH in conical flask/cm3 | Amount of Oxalic Acid used in titration/cm3 | - | (±0.06 ml) | (±0.1) | 1st | 25.0 | 20.60 | 2nd | 25.0 | 21.30 | 3rd | 25.0 | 21.05 | 4th | 25.0 | 20.60 |
Table 2:Collection of raw data
Average amount of {(COOH)2.xH2O} used:
=20.8875
≈20.9 (2 d.p)

Neutralization Equation:
(COOH)2 (aq) + 2NaOH(aq) (COONa)2(aq) + 2H2O (l)

Use N1 = M1V1 when M is in mol/dm3 N2 M2V2 1) n(NaOH)=0.025x0.1=0.0025mol 2) n(COOH)2 =0.00125mol 3) N1=M1V1
N2 M2V2

4) 1 = M1x0.0125
2 0.10.025 M1=0.58mol/dm3 5) Mol(COOH)=0.058x0.25= 0.0145mol 6) Mass(COOH)=0.0145x2(12+16+16+1)=0.841g 7) Mass(H2O)=1.5-0.841=0.659 8) Mol(H2O)=0.659 (1.01+1.01+16)
= 0.0366mol 9) Total Number of X= 0.0366 0.0145 =2(approx..)

Discrepancies: 1)We definitely had errors in many areas, such as we cannot really tell at which volume did the color change occurred.
2) The phenolphthalein indicator might be overly

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