Chemistry Ia Ib

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IB KYAW WAI IB1I KYAW WAI IB1I CHEMISTRY IA (2) TITRATION OF ACID & ALKALI Name: KYAW WAI Date: 5th February 2013 IA CRITERIA ASSESSED: DCP, MS Declaration I declare that this report I have submitted is my own original work and I have acknowledged the use of words or ideas of another person. Signature: ______________________________ Marks: ______________________________ Aim of the experiment: The aim is to determine the water of crystallization of a diprotic acid by titration against a base. Background: Many substances that we use are either acidic or basic. Because acids and bases can neutralize each other, that gives us a strategy for finding the unknown concentration of an acid or base when we react…show more content…
Tabulate the results in a neat tabular column. Data Collection: (a) Qualitative Data: Materials | Color/Observations | 1) Sodium Hydroxide | Colorless liquid | 2) Sodium Hydroxide after two drops of phenolphthalein | Pink to colorless liquid | 3) After titration with {(COOH)2.xH2O} | Change from black to colorless liquid | Table 1:Observation (b) Quantitative Data: Trials | Amount of NaOH in conical flask/cm3 | Amount of Oxalic Acid used in titration/cm3 | - | (±0.06 ml) | (±0.1) | 1st | 25.0 | 20.60 | 2nd | 25.0 | 21.30 | 3rd | 25.0 | 21.05 | 4th | 25.0 | 20.60 | Table 2:Collection of raw data Average amount of {(COOH)2.xH2O} used: =20.8875 ≈20.9 (2 d.p) Neutralization Equation: (COOH)2 (aq) + 2NaOH(aq) (COONa)2(aq) + 2H2O (l) Use N1 = M1V1 when M is in mol/dm3 N2 M2V2 1) n(NaOH)=0.025x0.1=0.0025mol 2) n(COOH)2 =0.00125mol 3) N1=M1V1 N2 M2V2 4) 1 = M1x0.0125 2 0.10.025 M1=0.58mol/dm3 5) Mol(COOH)=0.058x0.25= 0.0145mol 6) Mass(COOH)=0.0145x2(12+16+16+1)=0.841g 7) Mass(H2O)=1.5-0.841=0.659 8) Mol(H2O)=0.659 (1.01+1.01+16) = 0.0366mol 9) Total Number of X= 0.0366 0.0145 =2(approx..) Discrepancies: 1)We definitely had errors in many areas, such as we cannot really tell at which volume did the color change occurred. 2) The phenolphthalein indicator might be overly
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