Essay about Chemistry

This experiment is based on determining the chemical formula for a hydrated compound containing copper, chloride, and water molecules in the crystal structure of the solid compound, using law of definite proportion. The general formula of the compound is CuxCly•zH2O, and aim is to determine chemical formula of this compound.

= = == Calcium Carbonate + Hydrochloric Acid Calcium Chloride + Water + Carbon Dioxide Equipment ---------

b. Using the newsvendor model, Cu = 1 - 0.2 = 0.8 and Co = .2. Cu /(Cu + Co) = .8.

1. Suppose that you have an unlimited supply of copper (II) sulfate to react with iron. How many moles of copper would be

This is a simple equation that doesn’t properly prove the reaction. It is very complex and starts with this:

Example problem: How many grams of carbon dioxide are produced when 20.0 g acetylene (C2H2) is burned?

Co 2+ (aq) + 2 NO3- (aq) + 3 Na+ (aq) + PO4 3- (aq)  CoPO4 (s) + 3 Na+ (aq) + 2 NO3- (aq)

Purpose: The purpose of this experiment is to observe a variety of chemical reactions and to identify patterns in the conversion of reactants into products.

Finally, we measured the mass of the remaining copper in the test tube. This lead to the discovery that the mass of the copper in relation to our original 1.08 grams of copper oxide was 0.96 grams. From this data, we could find that the measurement of oxygen in our amount of copper oxide was 0.12 grams. With these significant weights, we were then able to convert those results to the amount of moles each element had in contribution to our total quantity of copper oxide. Specifically, we found that there was 0.015 moles of copper in our copper oxide, and 0.0075 moles of oxygen. So, that made the calculated ratio between moles of copper and moles of oxygen to be 2.0, or a 2:1 ratio of copper to oxygen. Thus, the formula of the red copper oxide can be expressed as . The lab worked the way it did primarily because of the chemical characteristics of copper oxide. Since the oxygen could separate from the copper when presented with a heat source, it allowed for the amount of each element in our quantity of copper oxide to be measured and then calculated into a ratio, which determined the formula for the

Mol of Cu = 0.035983 mol Fe * 1 mol Cu1 mol Fe = 0.035983 mol [III]

Changes in matter occur every day. There are two types of ways matter can be altered; physically and chemically. Physical changes do not change the composition of the matter while chemical changes occur when one or more substances turn into a completely new substance.

Density of solution = 100 cm3 x 1.00 g/cm3 = 100 g Temperature (K) = Temperature (C) + 273 △T= t final - t initial 304.26667-293.56667= 10.7 K moles(n)=molarity (mol dm3) x volume 2mol dm3 X 50 x 10 ˆ-3

Then you find the mole of Carbon from one singular C6H6, which is going to be

Weigh out the necessary grams of Copper Sulfate Pentahydrate. The 40-degree group weighed out 40 grams. (See Figure 1)

cos2 x = sin2 x + cos2 x sin2 x cos2 x cos2 x cos2 x = 1 2 cos2 x = RHS