Composition And Molecular Formula Of An Inorganic Double Salt

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The purpose of this experiment was to find the percent composition and molecular formula of an inorganic double salt. It was conducted using basic lab skills to create the double salt and then break it down into its four components: K, Ni, SO4, H2O. When the double salt had been broken down into its components it was found that it consisted of 17.9% potassium (K), 17.0% nickel(Ni2+), 45.3% sulfate (SO4), and 24.6% water(H2O). Creating a molecular formula of K2 Ni (SO4)2 (H2O)5. Experiment A) Double Salt Synthesis To start the experiment, a 150 mL beaker was weighed. By using the tare function, 6.619 g of nickel sulfate was added to 150 mL beaker. The substance was in the shape of crystals and had a teal green color. Then, 15 mL of deionized water was added to the beaker containing the nickel sulfate hexahydrate. The beaker was then set atop a hot plate and heated on setting four while constantly being stirred until the solid had dissolved. After the heating had occurred, the color of the liquid in the beaker was a light green color. The 150 mL beaker was taken off of the hot plate and set on a ring stand base to cool slightly. Next, on the same scale as before, 4.425 g of potassium sulfate was added to a 200 mL beaker. Then 50 mL of deionized water was added to the 200 beaker. It was heated at setting four on the hot plate and stirred until dissolved. Then warm nickel sulfate (150 mL beaker) was poured into the solution of hot potassium sulfate (200 mL beaker) and mixed

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