Connor Mcdavid: Fastest Skate In The NHL

The purpose of this lab was to test the relationship between velocity, position and time. As well as identify how accelerations affects an object's velocity and time. In this experiment, we will collect data on velocity, speed, and time. We used the equation Y=mx+b, in order to compare the velocity of each trial by comparing the slope and the y-intercept. If the slope was steeper on the graph, this meant that the cart had an increase in velocity. If the cart maintains at a constant speed, then the cart will have an increase in acceleration. In class we learned about the principles of acceleration, time, and velocity. Acceleration is an object’s increase in velocity. Velocity is how

I can be sure that I solve the equation correctly because I know line BF is 180 and I have the measurement of <AHB and <GHF and the work are shown above how I got the answer for A.

This is established by analyzing the kinematics and activation levels at various speeds, positions and phases of the wrist shot and skating. These articles provide insight on how activation demands change throughout certain hockey skills and can be applied to a training routine to improve performance. By using electromyography, motion capture systems and comparing high caliber and low caliber athletes, results such whole body stabilization, increased muscle activation and joint motion amplitude were observed with athletes showing higher skill and

41328.125 a = 41328.125 m/s^2 Then we take v = u +at where v is the final velocity of an object, u is the initial velocity, a is the acceleration and t is the time from u to v. u=0 v=230 m/s a=41328.125 m/s^2 230= 0 + 41328.125 x

Here, Sy is the displacement in the y (vertical) direction. Since the height of the cliff and the acceleration of the car (gravity) are known, time is the missing variable needed to find the horizontal displacement.

In the United States of America 64% of the population watch football, but no one ever thinks of the physics involved. One common misconception is people think that quickness and speed can go hand in hand, but in fact quickness and speed are 2 different things. Quickness is acceleration and that is the speed in comparison to direction. However speed is the rate of change per second. “Galileo was the first scientist to make a comprehensive study of kinematics” (pg. 27). How does physics relate to football? Football has many examples of how physics can be used to better understand it. another example is acceleration, even more acceleration versus speed. Speed velocity and acceleration are

Then I used the work-energy theorem to calculate the energy lost as heat, the work, as an object traveled a given distance on a sticky surface. Friction was a factor in that part of the problem so I drew a free-body diagram to indicate the net force acting on the object (WA-COMP-2009.SCI.1.1.3.H). Finally, I had to calculate the spring constant using the mechanical energy equation one more time, but replacing the gravitational potential energy equation with the spring potential energy equation to determine the spring constant (WA-COMP-2009.SCI.1.1.3.J). Problem eleven required the use of one simple kinematic equation, after I applied the impulse momentum theorem; once I determined the velocity of a skater, I used it to determine the time it took him to travel a given distance (WA-COMP-2009.SCI.1.1.3). Although I lost points on three multiple choice questions, they are no longer a weakness because I reworked the problems and have become proficient

Speed and agility are integral components of successful performance in a variety of different sports. Speed refers to the ability to move the body as quickly as possible over a set distance. Agility, on the other hand, is the ability to accelerate, decelerate, and change direction rapidly while maintaining good body control and speed. By measuring speed and agility, a fitness professional can target the weaknesses in sport or task performance and use them to alter the training program to make it more individualized to the athlete.

Substituting v from eq. 5 into eq. 4 and solving for v0 : v0 = m+M m 2gh = 2.00 kg + 0.0100 kg 0.0100 kg 2 9.80 m/s2 (0.0500 m) = 199 m/s

Use results above for equation of motion in y direction: y − direction : ⇒ For object B: 0 = TR − WB = 0 ⇒ WB = TR = T = 17.4 N 0 = 2T sin (35◦ ) − WA WA T = = 17.4 N 2 sin (35◦ )

Hockey, claimed by many to be one of the most intense and brutal games professionally

Many everyday activities, and sports involve physics. During the Olympics, you saw the graceful performance done by the figure skaters. Figure skating involves a lot of physics. These principles include friction, momentum, and Newton’s Third Law. These core principles plays a big impact on the performance of figure skaters. Before understanding the physics of the ice skater’s motion, the first thing to comprehend is the skates itself.

“Skating combines elements of athleticism and artistry, requiring strength, flexibility, power, endurance, and grace” as stated by the International Journal of Sports Physiology and Performance ( 2007). Skaters much have adequate aerobic endurance for performances, which can last up to 10 minutes as well as anaerobic capacities that can sustain bursts of energy for the many different types of jumps they present. These athletes commonly incorporate interval training into their programs as it alternates activities between high and moderate intensities, similar to what they will encounter during a performance.

(1.5 pts) Find Distance to Accelerate and Stop with a Single Engine Failure at V1 (ft).

Newton’s Second law states that the acceleration of an object is directly proportional to the net external force and inversely proportional to the mass of an object. Force and acceleration are both vectors and will point in the same direction. Newton’s third law states that forces occur in pairs, so when a force acts on an object there will be a reaction from the object to where the force is applied. The second object will exert a force back onto the original object that is equal in magnitude but opposite in the direction. Newton’s laws are able to yield the equation F=ma. In the case of figuring out the hockey shot a=(Vf2-Vi2)/2Δx, and when you combine the equation together you get F=m=(Vf2-Vi2)/2Δx. All that is needed to figure out the force on the hockey puck is the initial velocity, the final velocity, the mass and the distance traveled. The mass of a hockey puck is .160kg and the length traveled is 17.3 meters. The initial velocity of the puck in my case was 0 m/s and the final speed of the puck was 87 mph measured by a radar gun which converted to 38.89 m/s. With all this information the force could be calculated. F=.160kg(38.89 m/s 2 – 0 m/s 2)/2(17.3m) which equaled 6.99 N or 7.00 N.