Cru Computer Rental Case Solutions

1610 WordsJul 11, 20127 Pages
CRU Computer Rental Case Solutions Solution 1 TABLE 1: CRU FLOWS | Customer | Receiving | Status 24 | Status 40 | Stored Orders | Orders at Suppliers | Status 41 | Status 42 | Status 20 | | | | | | | | | | | Throughput(Units/Week) | 1000 | 1000 | 1000*.70=700 | 1000*.30+ .15*700= 405 | 405 | 405 | 405 | 405 | 1000 | | | | | | | | | | | Inventory(Units) | 8000= 8*1000 | 500 | 1500 | 1000 | 500 | 405= 405*1 | 500+405 = 905 | 500 | 2000=2*1000 | | | | | | | | | | | Flow Time(Weeks) | 8 | 0.5= 500/1000 | 2.14= 1500/700 | 2.46=1000/405 | 1.23= 500/405 | 1 | 2.23 | 1.23= 500/405 | 2 | Note:  Numbers in Black are given  Numbers in red are calculated by using formula Av. flow time =…show more content…
CASE 2 Flow time is same CASE 2 | Time spent in all buffers is the same as it was in last year | | | | OPTION A | Customer | Receiving | Status 24 | Status 40 | Stored Orders | Orders at Suppliers | Status 41 | Status 42 | Status 20 | Throughput(Units/Week) | 1260 | 1260 | 882 | 510 | 510 | 510 | 510 | 510 | 1260 | Inventory(Units) | 10080 | 630 | 1887 | 1260 | 627 | 510 | 1137 | 627 | 2520 | Flow Time(Weeks) | 8 | 0.5 | 2.14 | 2.47 | 1.23 | 1 | 2.23 | 1.23 | 2 | | | | | | | | | | | OPTION B | Customer | Receiving | Status 24 | Status 40 | Stored Orders | Orders at Suppliers | Status 41 | Status 42 | Status 20 | Throughput(Units/Week) | 1120 | 1120 | 784 | 454 | 454 | 454 | 454 | 454 | 1120 | Inventory(Units) | 8960 | 560 | 1677 | 1120 | 557 | 453 | 1011 | 557 | 2240 | Flow Time(Weeks) | 8 | 0.5 | 2.14 | 2.47 | 1.23 | 1 | 2.23 | 1.23 | 2 | | | | | | | | | | | OPTION C | Customer | Receiving | Status 24 | Status 40 | Stored Orders | Orders at Suppliers | Status 41 | Status 42 | Status 20 | Throughput(Units/Week) | 950 | 950 | 665 | 385 | 385 | 385 | 385 | 385 | 950 | Inventory(Units) | 7600 | 475 | 1423 | 950 | 473 | 385 | 857 | 473 | 1900 | Flow Time(Weeks) | 8 |

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