# Cru Computer Rental Case Solutions

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CRU Computer Rental Case Solutions Solution 1 TABLE 1: CRU FLOWS | Customer | Receiving | Status 24 | Status 40 | Stored Orders | Orders at Suppliers | Status 41 | Status 42 | Status 20 | | | | | | | | | | | Throughput(Units/Week) | 1000 | 1000 | 1000*.70=700 | 1000*.30+ .15*700= 405 | 405 | 405 | 405 | 405 | 1000 | | | | | | | | | | | Inventory(Units) | 8000= 8*1000 | 500 | 1500 | 1000 | 500 | 405= 405*1 | 500+405 = 905 | 500 | 2000=2*1000 | | | | | | | | | | | Flow Time(Weeks) | 8 | 0.5= 500/1000 | 2.14= 1500/700 | 2.46=1000/405 | 1.23= 500/405 | 1 | 2.23 | 1.23= 500/405 | 2 | Note:  Numbers in Black are given  Numbers in red are calculated by using formula Av.…show more content…
Line Depreciation= 8634*1000/156= 55346 Profit = 144000-67878-55346= \$ 20782 (GAIN) Above results shows that the sales drive was not very effective. Suggested Plan? (Capturing market for longer period) Solution 6 In order to solve this problem we will first find computers rented per week. Computers rented per week: Option A: .6*1500+.3*1000+.1*600= 900+300+60= 1260 Option B: .4*1500+.4*1000+.2*600= 600+400+120= 1120 Option C: .2*1500+.5*1000+.25*600= 300+500+150= 950 CASE 1 Inventory size is same CASE 1 | Buffer Sizes are same | | | | | | | OPTION A | Customer | Receiving | Status 24 | Status 40 | Stored Orders | Orders at Suppliers | Status 41 | Status 42 | Status 20 | Throughput(Units/Week) | 1260 | 1260 | 882 | 510 | 510 | 510 | 510 | 510 | 1260 | Inventory(Units) | 8000 | 500 | 1500 | 1000 | 500 | 405 | 905 | 500 | 2520 | Flow