Data Analysis In analyzing the data I collected I found that the average age of the survey respondents was 22.32. The median age of the respondents was 21 years old. The youngest respondents to my survey were 18 years old and made up twenty-nine percent of the participants; the oldest respondent to my survey was 56 years old. Twenty-eight of the thirty-one respondents were 26 years of age or younger at the time they completed the survey. The variance of respondent age is 47.95. The standard deviation came out as 6.92. 47.95 As a variance, means that the data points tend to be spread out from the mean and each other. 6.92 as a standard deviation further illustrates that the data points for this variable spreads out. This is mainly because I had one respondent who was 56 among many younger respondents, throwing off the consistency in age. A majority of the survey participants were male. The responses of 23 males and 8 females made up my survey data. The mean for gender is .74, meaning that there is overall more male participants than female participants in my survey, since 1 represented males and 0 represented females. The mode is 1; there were more males in all. The mode for this variable is also 1. The variance of respondent gender is .19. The standard deviation for this variable came out as .44. The variance of .19 for this variable indicates that the values and data points tend to be very close to the mean. The standard deviation of .44 also illustrates the values and
1. For the following scores, find the mean, median, and the mode. Which would be the most appropriate measure for this data set?
Standard deviation is a way of visualizing how spread out points of data are in a set. Using standard deviation helps to determine how rare or common an occurrence is. For example, data points falling within the boundaries of one standard deviation typically account for about 68% of data and those between (+/-)1 standard deviation and (+/-)2 standard deviations make about 27% combined. This can be better visualized by using a bell graph. Using the mean and standard deviation, the points where standard deviations occur can be drawn on the graph to better understand which data is rare and which is common.
I conducted a survey, asking 20 females and 20 males their favorite food group for my AP Statistics project. I surveyed on Wednesday, September 27 and on Thursday, September 28 at Marshall High School. They chose from protein, grain, vegetables, fruit, and dairy. From the data, I found that 10 males and 2 females liked protein best, 3 males and 2 females liked grains best, 1 male and 1 female liked vegetables best, 3 males and 13 females liked fruit best, and 3 males and 2 females liked dairy best. Half of the males liked protein best, while most females liked fruits best. The least amount of both males and females liked vegetables. From this data, we can see that males like protein more than females do, and females like fruit more than males
Standard Deviation of Mean= 0.4762Standard Deviation of Median= 0.7539The standard deviation of the Mean is smaller, which means all of the data points will tend to be very close to the Mean. The Median with a larger Standard Deviation will tend to have data points spread out over a large range of values. Since the Mean has the smaller value of the Standard Deviations, it has the least variability.
5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?
2. Sort the data by Gen or Gen 1 (into males and females) and find the mean and standard deviation for each gender for the following variables: Use the descriptive stats function for one gender and the Fx functions (average and stdev) for the
1. For the following scores, find the mean, median, and the mode. Which would be the most appropriate measure for this data set?
The first variable was the number of total prior arrests. The mean was 10.54. The median was 5 and the mode was 0. The most appropriate measure of central tendency for this set of data is the mode. The mode is most appropriate because out of 962 people 290 people had 0 prior arrests. The other numbers of arrests were not even close with the
Based on the given sample of student test scores of 50, 60, 74, 83, 83, 90, 90, 92, and 95 after rearranging them from least to greatest. As the mean is based on the average of sum, the average of this sample is 79.67 or 80. The mode refers to numbers that appear the most in a sequence and in this case 83 and 90 both appear twice. Range calculates the difference between the largest and smallest number, which are 95 and 50 which have a difference of 45. The variance is the difference between the sum of squares divided by the sample size, which is the number in the sample minus one (Hansen & Myers, 2012), meaning it takes each number of the set and subtracts
Read the directions and write answers independently. 1. (L.2) Choose the sentence with correct capitalization and punctuation. A. Mrs. Brown catches the bus at the corner of Elm and N. Grove.
5. The standard deviations of the groups are different between these two data sets. This implies that both girls and the boys groups have a large variability in their data. The reason is that the standard deviation for boys is 5.9 and the standard deviation for girls is 5.0. This means the data has a wide range of data within the mean.
Who listens to R&B music more females or males? We guessed that more females listened R&B music than males. After interviewing a group of males and females I was able to come up with the conclusion that more females listened to R&B music than most males. All of these participants were handpicked from a sociology class. These participants consisted of nine males and nine females. I choose to ask students who were either in band or those who listened to online radios on daily basis. Finally, I asked each participant how many R&B songs they listen to in one day. In the first paragraph, describe the statistical analyses you performed. The data that I gathered showed that females listened to more R&B songs in a day than males do. Chart 1 shows
The summary includes variance, mean, median, mode and standard deviation. As shown in the histogram majority of people in the data pool have a height of 62-68 inches. This is a symmetrical distribution seeing how close the mean and median are to each other.
Mode/median: these two data were very similar scores. Sex had a mode and median of 0, age had median of 112.5 and mode of 113, prim dis mode and median of 1 and lastly, therapist mode and median of 2.
The mean, average of the population, the standard deviation, deviation in the sample, and a histogram, a graph to show the percentage of the population, was prepared. The means calculated as follows: blue 0.2072, orange 0.2271, green 0.1852, yellow 0.1165, red 0.1448, and brown 0.1192. The histogram was bell shaped with three outliers, numbers outside the given range, of 55 candies, or one bag.