Density and Answer

(a) What is the capacity (saturation missing ratio) of the rising air at 3000 feet?

3. Calculate the N component of a resultant 32.5 m/s, 35.0 º E of N.

SQRT(2 * F * T / H) = (2 * 80 * 200,000 / 1.00)0.5

But per the question, we need to use (2 x 10^8 m/s) for the propagation delay.

Would pressure be generated if you had 9 mM albumin on one side of a 200 MWCO membrane and 9 mM NaCl on the other side? If so, which solution was generating the pressure? pressure would be present due to different concentrations which are not equal.

Set the radius to 2.0 m, the mass to 1.0 kg, and the velocity to 10.0 m/s.

Using Gravitational Force as a Measurement Tool Answer the following questions about the results of this activity. Record your answers in the boxes. Send your completed lab report to your instructor. Dont forget to save your lab report to your computer Activity 1 Record your data from Activity 1 in the boxes below. Enter the data for the sample you used in each trial (5000 rpm, 10000 rpm, etc) in the appropriate columns and the corresponding g-force, number of layers, and position of layers position results. You will need to use the following formula to assist with your laboratory report G-force 0 00001118 x radius of centrifuge arm x (rpm)2 The radius of the centrifuge arm for this instrument is 10 cm. Speed 5000 rpm 10000 rpm 15000 rpm

As a result of the experiment and computation of data, the aerofoil was found to have a critical Mach number of M=0.732. Below this freestream Mach number the Prandtl-Glauert law predicted results very

T= 40ms, I figured this by guessing cause I could not find any information on how to calculate. So I used the equation for t and plugged in different numbers until I got the 10ms that was already given in the table. t= T x 0/360= 40ms x 90/360= 0.01 x 10^-3= 10ms

Use Equation v2= (r/m)Fc [1] and [4] to solve for T. From this equation, determine what should happen to T as Fc is increased. Circle it on Data Sheet A.

2) A boat can move at 30 km/h in still water. How long will it take to move 12 km upstream in a river flowing 6.0 km/h?

The clock would lose time because as the value of g decreases, the period increases.

* f times c = λ (where c is the speed of light: 3 x 108 meters / second)

Notice how it barely exceeds 0.5 m/s2 and averages only (0.14±0.03)m/s2 which is far from 1 m/s2.)

Step 8: We can now plot our values into the rearranged equation to figure out acceleration due to gravity ‘g’. (Eg. (4π2 x 43.70)/ 1.758 = 981.4 cm/s2)