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Density of Liquids Lab Report Paper

Decent Essays

FE 106

GENERAL CHEMISTRY

EXPERIMENT-1

DENSITY OF LIQUIDS

PREPARED BY BURAK COBAN

PURPOSE:

In this experiment we will learn how can we find the density of liquids and liquids of density how change effect of temperature, pressure, mass, volume and concentration. For this reason we will take NaCI solutions with different concentrations and we will measure their densities, so we will find out the effects of concentration on density of solutions.

THEORY:

Density is a physical property obtained by dividing the mass of a material or object by its volume (i.e., mass per unit volume). Here is an old riddle:” What weighs more, a ton of bricks or a ton of feathers?” if you answer that they …show more content…

The densities of the NaCI solutions were calculated.

And then a sample of NaCI solution, which we didn’t know its concentration, was added to the empty graduated cylinder.

Mass of the unknown solution (U1) was found.

Finally Density of the unknown solution was calculated.

RESULTS (DATA):

a) Density of water;

Temperature of water: 24 0C

Mass of graduated cylinder (m1 ) : 29,95 g
Volume of water: 20 ml.
Mass of water + graduated cylinder: 49,90 g
Mass of water: 19,95g

Density= (19,95)/ 20= 0,9975 g/ml

Formula of Percent Error:

| T.V. - E.V.| _____________ *(100) |T.V.|

T.V.= Theoretical value.

E.V.= Experimental value.

Percent Error: ( |0,9964- 0,9975| / 0,9964)*100= 0,11%

b) Density of solutions:

Volume of solution: 20 ml

4% concentration =((50,91-29,95)/ 20)= 1,048 g/ml

8% concentration =((51,18-29,95)/20)= 1,0615 g/ml

12% concentration =((51,47-29,95)/20)= 1,076 g/ml

16% concentration =((51,95-29,95)/20)= 1,10 g/ml

Unknown concentration (U1):

U1 ((50,60-29,95)/20)= 1,0325 g/ml

DISCUSSION:

In this Experiment, We were learned how can we find the density of the liquids, by using the formula. But we found different results some of them. For example

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