Determination of the Concentration of Acetic Acid in Vinegar

926 WordsNov 21, 20124 Pages
Determination of the Concentration of Acetic Acid in Vinegar Lab Exercise 4 CHEM 1106 9/19/12 Purpose: Standardize a sodium hydroxide solution using a primary standard acid. Determine the molarity and the percent by mass of acetic acid in vinegar by titration with the standardized sodium hydroxide solution. Introduction: Vinegar is a dilute solution containing acetic acid. Since vinegar has a low pH, it can be titrated with a base. Titration is a method used in order to ascertain the amount of a constituent in a solution by measuring the volume of a known concentration of a reagent required to complete a reaction with it, typically using a burette. The equivalence point of a titration occurs when chemically equivalent…show more content…
= 0.8515 M CH3COOH Calculate the percent by mass of acetic acid in vinegar: 0.0020 L CH3COOH x 0.8515/1 L soln. = 0.001703 mol CH3COOH 0.001703 mol CH3COOH x (60.06g CH3COOH/1 mol CH3COOH) = 0.1023g CH3COOH 2.0 mL CH3COOH x (1g CH3COOH/1 mol CH3COOH) = 2.0 mL CH3COOH soln. Equation 2 of CH3COOH = (0.1023 g CH3COOH/2.0g CH3COOH) x 100% = 5.115% Final Answer: Molarity of vinegar: 0.8515 M CH3COOH Percent mass: 5.115% CH3COOH From the plots determine

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