The purpose of this experiment was to examine the permeability of the dialysis tubing using molecules of various sizes (iodine, water, glucose, and starch) and reagents to help identify the molecules in the solution. It was assumed that iodine, then water, followed by glucose and starch respectively, would have the most ease of movement, as they are in the order of size (least to greatest). Being an element, iodine is the most minuscule out of the four, as they are the building blocks for molecules, such as: water (H2O). As a result, iodine was able to move with ease through the dialysis tube from the beaker with water, which was indicated by the tints of black and purple in the dialysis tube, as a result of the reaction between this element and starch. Consisting of molecular compounds, carbohydrates are created with the three elements, carbon, hydrogen, and oxygen in a one to two to one ratio. …show more content…
When glucose comes in contact with Benedict's solution and is heated, the color of the solution turns into a mango-orange, which did occur with the solution in the beaker, indicating the presence of glucose. Meanwhile, when starch interacts with iodine (Lugol’s solution), a green hue is apparent; however, it quickly transforms into an opaque black. Because glucose was smaller in size, as it is formed with only one saccharide, it was capable of moving through the dialysis tube into the beaker. This was assumed as the mass of the dialysis tube decreased from 60.06 grams to 59.92 grams, and since the solution in the beaker did not turn in blackish, which indicated direct contact between iodine and starch, a bit of glucose travelled out. In addition, according to the results, starch was unable to because its molecules were too large to travel through the pores of this semi-permeable membrane, as it is formed with more than two simple
The dialysis tubing used was meant to act as a semi-permeable membrane, which allows molecules that are smaller in size to pass through it. Molecules that it allows are water, Lugo’s, and glucose. However, starch is too big to pass through this membrane. Amylase can digest starch and turn it into glucose, thus
2. What molecules remained inside of the dialysis bag? The starch had remained inside of the dialysis bag.
Dialysis tubing is a membrane made of regenerated cellulose fibers formed into a flat tube. If two solutions containing dissolved substances of different molecular weights are separated by this membrane, some substances may readily pass through the pores of the membrane, but others may be excluded.
In this lab we found out that the dialysis bag contained more fluids inside it. This can happen because sucrose is small enough to pass through the selectively permeable membrane. Some errors that might have been encountered during the lab could have been the fact that some of the dialysis bags were not tightly tied with the dental floss, or that the wrong substance was used. Another possible source of error was if the carrot strips had been dehydrated from the beginning of the experiment or were already
Certain substances are able to diffuse across plasma membranes under the right conditions through selective permeability. The selection of these certain substances allows for cells to maintain homeostasis, as these substances move from higher concentration to lower concentration. The purpose of this experiment is to see whether or not Lugol’s will be able to diffuse across dialysis tubing, which acts as a membrane. Lugol’s turns black when it interacts with starch, which will make the diffusion easy to see. This is all based off of a caterpillar eating a plant. The starch present in the leaves causes the caterpillar to produce amylase, which breaks down starch. In one experiment, the tubing will contain starch and amylase, while the other tubing
In this lab experiment, half our group observed and measured osmosis using dialysis tubes that were represented as the semipermeable membrane. It is permeable to water and other small molecules but is impermeable to larger molecules such as the sucrose solution used in each of the four beakers and tubing. The other half of our group observed the tonicity of sheep blood to determine whether the blood was isotonic, hypotonic, or hypertonic. The 85 g/dL of NaCl solution was the ideal isotonic number in relation to the sheep blood cells as well as a reference to the other observations of the solutions.
The independent variable was the concentration of sucrose in the dialysis tubing we used as a simulated membrane.
When glucose carriers in the membrane were set to 500, the glucose transport rate for 2.00 mM of glucose was .0008 mM/min. Equilibrium was reached at 43 minutes. At 700 glucose carriers the rate was .0010 mM , and equilibrium was reached at 33 minutes. When the glucose carriers was set at 900 the rate was .012 mM/min, and equilibrium was reached at 27 minutes. After changing the glucose concentration to 8.0 mM, the glucose transport rate with 500 carrier proteins was .0023 mM/min, and equilibrium was reached at 58 minutes. With the simulation set at 700 carrier proteins the rate was .0031mM/min, and equilibrium was reached at 43 minutes. When the simulation was done with 900 carrier proteins the glucose transport rate was .0038, and equilibrium was reached at 35 minutes.
Table 1 shows the contents of the bags and the content of the concentration it was submersed in. Bags 2-4 each contain a solution of both sucrose and water. These bags were each put into beakers containing hypertonic solution. These bags gained weight over time because the water moved from its high concentration inside the beaker to the low concentration inside the membrane of the artificial cell, the membrane being the bags that consisted of dialysis tubing. The
A cell, the building block of all living organisms, is composed of four fundamental biomolecules: proteins, carbohydrates, sugars and lipids. Proteins provide a vast amount of functions cells such as they serve as enzymes, provide structural support to cells, and act as antibodies. Reagents are used to spark a chemical reaction. The reagent used to detect protein traces in a substance is Biuret’s. Biuret’s will turn purple if proteins are present and blue if they are none. Biuret’s copper particles, have a charge of +2, are diminished to a charge of +1 when peptide bonds, which are in proteins, are present, creating the color change. Polysaccharides, which are carbohydrates, are most notably known to provide energy to the body, but they also help in breaking down fatty acids. Iodine is the reagent used to determine whether a substance has starch in it. The iodine/starch complex has energy levels that are only for retaining unmistakable light, giving the complex its extraordinarily dark black-blue shade. If there is no starch found, iodine will remain its natural yellowish-brownish color, but if starch is present, iodine will turn blue-black. Monosaccharides, which are sugars, like polysaccharides, provide the body with energy. To detect monosaccharides, the reagent, Benedict’s, is used. Benedict’s reagent is added to a test tube, then it is placed in
The major objective of the experiment was to test the effect of the concentration gradient on the diffusion rate. It was hypothesized that the greater the stronger the concentration gradient, the faster the rate of diffusion would be. To test this, dialysis tubes were submerged in different concentration fructose solutions. We weighed the tubes at specific time intervals to measure the rate of diffusion of water in each different solution. The results illustrated that increased concentration gradient increases the rate of diffusion of water in the tubes. We concluded that as concentration of the
0.0375 mg/ml Porcine Pancreatic Amylase Solution (amylase powder in 0.9% NaCl ), Iodine Solution; each solution were pipetted into each of the 5 test tubes with 5 ml of 1% starch. Each tube contained a 1% starch solution with a different pH. All tubes were at room temperature. Room temperature was 22C. 0.2 ml of porcine pancreatic amylase solution was then pipetted into each tube. A timer was started and every 3minutes the starch / amylase mixture were pipetted from each tube and pipetted into the spot plate for every sample tube, then the iodine solution were added to a spot plate cell for each sample. Iodine reacts with starch to change from yellow to deep blue /black in the presence of starch. A lightening of the blue/ black to a brown color will occur as less starch is present. Results were reported as (+) for presence of starch in the sample or (–) for the absence of starch. After every three minute increment had passed, these same
(6.2)Material and Methods in the process or exercise of measuring the starch we were used the following material and how we used them to conduct the experiment. Obtain seven tubes the material to be tested table 6.1 and then add seven to ten drops of iodine to each tube, and then record the color of the tubes contents in table 6.1
Which allows small molecules such as water to pass through but it does not allow large molecule in order to test its permeability we made sure that there is difference of solute concentrations on two side of the membrane we made two bags of dialysis tube and the first dialysis tube contain glucose 1% starch and 1% albumen substances the other two tube contain chloride ion and sulfate ions which we placed the three tubes in a small dish filled with the external solution which is the distilled water to be underwater. are hypothesis that if the size of the compound is smaller than potassium permanganate then we expected that all compounds or substances smaller than potassium will permeate from the inside of the membrane to the outside the and the second hypothesis that we conclude as a possibility is that if the compound is a saccharide then the compound will permeate from the inside of the membrane towards outside of the membrane. As a group we predicted that glucose chloride ions and sulfate will go through the membrane because there is an imbalance of concentration solution and the size of the molecule is smaller than a saccharide molecule so therefore a +
By examining the filtration results, we can predict that the molecular weight of glucose must be