Enthalpy Change Lab Report

(.1063 KIO31) (1 mol KIO214 g) x 6 mol S2O41 mol KIO= .00298.04150= .259 M

The main objective of this experiment is to differentiate between a physical change and a chemical change.

This reaction is exothermic, meaning it releases heat when reactants are converted into products. The negative change in enthalpy (∆H° = -36,757 J) for this reaction indicates that the reaction is losing heat to its surroundings.

(0.074 mol HCl x 1 mol NaOH) / 1 mol HCl = 0.074 mol NaOH

Enter the precise mass in GRAMS of the potassium iodate used to prepare your primary standard solution.

11. Use the equation: q = m(SH)ΔT to solve for the specific heat of the metal.

9. Each of the other solutions is already approximately 0.1 M. With these solutions you can pour a small

6. Restate your predictions that were correct and give the data from your experiment that supports them. Restate your predictions

molality m= (grams MgCl2÷95.21gmol of MgCl2)10mL H2O×1g H2O1 mL H2O×1 kg H2O1000 g H2O+grams of ice×% of ice melted×1 kg ice1000 g ice

7. In a procedure developed to determine the percent zinc in post 1982 pennies, 50 ml of an HCl solution was used to react (dissolve) all of the zinc in the penny. To ensure complete reaction, the solution contains twice as many moles of HCl that is actually needed. What concentration of HCl should be used?

The purpose of this experiment was to find the amount and percent of water in a hydrated salt. Hydrated salt contains water molecules chemically bound to it while anhydrous salt is a substance that fire can readily remove the water molecules. Using the gravimetric analysis method, the sample salt was measured, heated, and was measured again after cooled down to room temperature; this procedure allowed the weight of water lost in the salt to be obtained. After two trials, the water in the salt was determined to have an average percent water of -35.04%. The null hypothesis, the heat will not affect the amount of water lost, was rejected ,however, the alternative hypothesis, the heat will allow for there to be water lost, was not supported.

Hypothesis: Reaction 3 will create the highest exothermic reaction in the test tube this is because the chemicals are highly flammable the means they are high in exothermic relations. If we use 4 grams of zinc powder the chemical retain with the copper sulphate solution will create the highest temperature We changed the

Mol of Cu = 0.035983 mol Fe * 1 mol Cu1 mol Fe = 0.035983 mol [V]

Weigh out the necessary grams of Copper Sulfate Pentahydrate. The 40-degree group weighed out 40 grams. (See Figure 1)

The main objective of this experiment is to carry out qualitative analysis to identify metal cations in unknown solution 1.