Finding the concentration of a Potato cell.

An investigation to find the water potential of potato and carrot tubers in a sucrose solution, of concentration 0.00 – 0.50Mol, over a 24 hour period

First, we estimated the osmolarity of potato tuber cells by measuring the change in the potato’s’ weight after they were incubated in various concentrations of sucrose solutions (0.1, 0.2, 0.3, 0.4, 0.5, 0.6 M). First, we obtained 100mL of distilled water, and 100mL of each sucrose solution-which we placed in separate 250mL beakers. We then used a cork borer to extract 7 cylinders of potato. We then cut them all to about 5 cm long, and removed the skin from the ends. We placed all seven potato samples in a covered petri dish so they would not dry out. For consistency, we assigned each person their own, separate task to perform to each potato cylinder. First, one person removed the potato cylinder from the petri dish and used a paper towel to blot. Then

If I am to figure out the estimated concentration of sucrose found naturally inside the potato using osmosis, then there will be a change in the mass of the potato because it will either be hypotonic or hypertonic to the cell, as it will affect the size of the cell along with in. The 0 M, 0.2 M, and 0.4 M solutions were are hypotonic to the cell. Hence, they contained less solute than the potato itself. Therefore, the potato cell increased in mass because water was moving into the cell. It was more concentrated had less water in comparison with outside the cell, so it moved in. However, the 0.6 M, 0.8 M, and 0.10 M solutions were hypertonic to the cell, causing the potato cell to decrease in mass as water was moving out of the cell. There was

Purpose: To determine the concentration of solute in the potato’s cytoplasm by measuring the change

However one beaker received 100 mL of Deionized water with a molarity of 0.0. Afterwards a cork borer was pushed through the potato and was twisted back and forth. Once the borer was filled it was removed from the potato. Pushing the potato cylinder out of the borer, this this step was repeated six more times in order to get seven undamaged potato cylinders. Using a sharp razor blade, the potato cylinders were both cut to a uniform length of about 5cm, and were removed of their potato skins. The potato pieces were also cut in half to give the cells a greater surface area in which it was easier to absorb the solution. After the cylinders were weighed on a balance and the data was recorded in Table 4. Using the razor blade each potato was cut lengthwise into two long halves. Then the potato pieces were transferred to the water beaker and the time they were submerged was recorded. This step was repeated for all potato cylinders in which the pieces were placed in solutions 0.1 to 0.6 M. The potatoes were incubated for ninety minutes. At the end of the incubation period the time was recorded. Then the potato piece was removed form the first sample. Next potato pieces were weighed the and the final weight was recorded in Table 4. This procedure was repeated until all samples had been weighed and recorded in the chronological order they were initially placed in the test solution. Afterwards the table was completed by recording the

Osmosis is a special type of diffusion. It is the diffusion of water molecules across a semipermeable membrane (a membrane that allows for the diffusion of certain solutes and water) from an area of higher water concentration to one of lower water concentration. For example, if a 1 M aqueous starch solution is separated from a .5 M aqueous starch solution by a semi-permeable membrane, then water molecules will move from the .5 M aqueous starch solution (higher water molecule concentration) toward the more concentrated 1M starch solution (lower water molecule concentration) until an equilibrium of water molecules exists between the two solutions. Since the semi-permeable membrane did not allow for the passage of starch molecules, the 1M-starch solution will gain in volume as the water moves in (Figure 3).

Figure 1: Percentage change in potato tuber mass vs. sucrose concentration. The percent change in mass decreased as the sucrose concentration increased. Relative osmotic concentration was measured as the percent change in mass of sucrose concentration over one hour.

My prediction is that as the concentration increases, the potato cell will lose more weight. This is because of the osmosis of water particles from the potato cell cytoplasm to the solution, resulting in a loss of weight. As the concentration decreases, the potato will lose less weight until a certain point where the osmosis of particles in and out of the potato cells will be equal. I also predict that as the salt

The aim of this experiment was to test the effect of surface area on osmosis and the effect of solute concentration on osmosis. To test this aim to hypotheses were devised. 1) If potato pieces are immersed in various salt solutions, then the pieces with the greatest surface area to volume ratio will experience the greatest weight change, because more water can move by osmosis across the potato cell’s semi permeable membrane. 2) If potato pieces are immersed in various salt solutions, then the pieces immersed in the most concentrated solution will experience he greatest weight change,

Most of the results of the experiment show that as the molarity of sucrose in the solution increases, the percent change in mass of the potato decreases. This is due to osmosis, water moves from a higher water concentration area to a lower water concentration area. From the results table, one can see that the mass of potato in the 0.1M sucrose solution increased by 13%, and the mass decreased by 28% in the 1.0M sucrose solution.

As we can see in Figure’s 1.2 and 1.3, when there was no sucrose solution, the potato increased in weight. This is due to the fact that the sucrose solution was hypertonic in comparison to the potato slice. Through osmosis, the solution moved along the concentration gradient and into the potato slice making it hypotonic. When there were higher concentrations of sucrose solution, the potato decreased in weight. This is due to the fact that the potato was hypertonic in comparison to the potato. Through osmosis, sucrose from the potato moved along the concentration gradient out and into

How do different concentrations of sucrose solutions (0M, 0.2M, 0.4M, 0.6M, 0.8M, 1M) affect the mass of potato cores when in sucrose solution?

Then, each group of students received the necessary materials to complete the experiment. When the students received the cups, they labeled cups to distinguish between the salt solution, distilled water, and control group. After weighing the cups and finding the mass of the cucumbers, the students poured 50 ml of water in one cup, 50 ml of salt solution in the other, and left the control cup empty. Then, the students placed the cucumbers into the cups and waited 30 minutes for the results. After the 30 minutes, the students removed the cucumbers from each solution and dried the cucumbers with paper towels. The students then weighed the cucumbers again and recorded their results. Lastly, the students found the difference from the original mass of the cucumbers and recorded their results.

Data: Effect of Solute Concentration on Osmosis in Potato Cells (for the 6 groups of our class)

First I gather all my materials needed for the experiment (see materials list). Second I peel and slice potatoes weigh each potato in grams. Get these slices to weigh the same in mass because if they vary to much in mass that could affect the results of the experiment. Third I place each potato in its own beaker. Fourth once the potatoes are placed in beakers I make sure to place enough solution to fully cover the potato. Each beaker should have a different amount of