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Freezing Point Depression Experiment

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The freezing point of a substance is when the substance turns from a liquid to a solid. The freezing point of a solvent can be decreased by adding a solute and making a solution, which is a freezing point depression. From knowing the temperature difference between a pure solvent and a mixture, it is possible to find the molar mass of the solute. To begin the experiment, students first obtain a LabQuest with a temperature probe. First, you retrieve about 20gs of t-butyl alcohol and put it in a pre-massed test tube. Students then prepare one beaker with ice water and another beaker with warm water. Students will first put the t-butyl alcohol into warm water to prevent it from freezing in room temperature, and put the temperature probe in the test tube. Afterwards, students will place the test tube containing the t-butyl alcohol and put it in the ice water until the temperature begins to …show more content…

First, students find the average temperature of the solvent by averaging the two temperatures found with the test tube with only the t-butyl alcohol. Students then find the freezing point of the t-butyl alcohol and the unknown mixture through using an equation that goes Temp =(m2b1-m1b2)/(m2-m1). From our lab group experiment, the average temperature of the pure t-butyl alcohol was 23.1 degrees Celsius and the mixture was 12.0 degrees Celsius. After finding the two temperatures, we subtracted the average temperature of the t-butyl alcohol and the freezing point of solution to get 11.1 degrees Celsius. Then, we divided the 11.1 by 8.37 °C/m to get the molality, which was 1.32616 m. Afterwards, we found the moles of solute by multiplying the kilograms of the t-butyl alcohol (0.01898 kg) by the molality to get 0.025170 moles. To find the molar mass, you divide the mass of the unknown by the moles of the unknown. When our group did these steps, we got an answer of 125.5 g/mol as our final

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