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Gas Chromatography Lab

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Introduction: Using the analytical methods of Gas Chromatography and Mass Spectrometry, in order to determine the composition of a mixture and its individual pure compounds. This is done by analyzing the mixture of compounds using Gas Chromatography and the individual pure compounds by using Mass Spectrometry. Experimental Procedure: Obtain a screw cap and vial which will be ran in the Gas Chromatograph. Fill vial no more than half full of pre prepared unknown compound which is dissolved in either ethanol or acetone. Place vial in Gas Chromatograph and follow the instruction in order to analyze unknown compound. Print out a copy of the results from the Gas Chromatograph. Obtain a mass spectrum for the unknown component in the liquid sample. Data and …show more content…

The first peak at 5.82 minutes represents the solute and the second peak at 6.04 minutes represents the solvent. It is heterogeneous since the results show more than one component in the original liquid sample. The conclusion is that the solvent was ethanol. This was because the second peak which was a retention time of 6.04 minutes matches the standard for ethanol which is also 6.04 minutes. Mass Spectrometry Results: Observation: There is a pair of high masses values which peak at 78 m/z at an intensity of 1.5 and 80 m/z at an intensity of 0.5. Conclusion: The pair of peaks can be used to determine that the parent ion is Chlorine. First, the ratio between Chlorine 35 and Chlorine 37 is 100 to 32.5 respectively which matches the 3:1 ratio which is presented by the two peaks. In addition, when doing mass subtraction for each peak, (78-35 and 80-37) it results in the same mass of 43 amu. This matching mass shows that chlorine is the parent ion because the highest peak is 43

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