Heats of Reaction Lab Report
Purpose: To measure the heats of reaction for three related exothermic reactions and to verify Hess’s Law of Heat Summation.
NaOH(s) ( Na+(aq) + OH-(aq) ΔH = -10.6kcal/mol
NaOH(s) + H+(aq) + Cl-(aq) ( H2O + Na+(aq) + Cl-(aq) ΔH = -23.9kcal/mol
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) ( H2O + Na+(aq) + Cl-(aq) ΔH = -13.3kcal/mol
Background: Energy changes occur in all chemical reactions; energy is either absorbed or released. If energy is released in the form of heat, the reaction is called exothermic.
If energy is absorbed, the reaction is called endothermic.
Materials: spatula sodium hydroxide pellets (NaOH) 1 Styrofoam cup 1.0 M sodium hydroxide (NaOH) 1 100-mL graduated
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Determine the change in temperature for each reaction. Show work here and record your answer in Data Table 2. 2. Calculate the mass of the reaction mixture in each reaction first by determining the volume of the solution and then assuming that the density of the solution is the same as pure water (1.0g/ml). Show work here and record your answer in Data Table 2. 3. Calculate the total heat released in each reaction, assuming that the specific heat of the solution is the same as for pure water (4.18J/gK). Use q=mcΔT. Show work here and record your answer in Data Table 2. 4. Calculate the number of moles of NaOH used in reactions one and two. Show work here and record your answer in Data Table 2. 5. In reaction three, the number of moles of NaOH can be calculated from the concentration of the solution (1.0M = 1.0mole/L) and the volume used. The calculation is below. Enter the result into Data Table 2. 50.0ml NaOH x 1mol NaOH = 0.050mol NaOH 1 1000ml NaOH 6. Calculate the molar enthalpy in Joules per mole of NaOH for each reaction. Show work here and record your answer in Data Table 2.
Data Table 2: Results of
2) (0.3 g NaBH4 x 154.16 g ethyl vanillyl alcohol) / (37.83 g NaBH4) = 1.223 g ethyl vanillyl alcohol
An Investigation into the Enthalpies of the Combustion of Alcohols = == == == ==
In order to measure the heats of reactions, add the reactants into the calorimeter and measure the difference between the initial and final temperature. The temperature difference helps us calculate the heat released or absorbed by the reaction. The equation for calorimetry is q=mc(ΔT). ΔT is the temperature change, m is the mass, c is the specific heat capacity of the solution, and q is the heat transfer. Given that the experiment is operated under constant pressure in the lab, the temperature change is due to the enthalpy of the reaction, therefore the heat of the reaction can be calculated.
Is this reaction endothermic or exothermic? What does that mean and how do you know? (~3 sentences)
How many moles of NaOH would be needed to completely react with all of the excess HCl determined in problem 8?
The results showed the molarity of the NaOH solution. This experiment was completed twice and a new average molarity
In your laboratory notebook sum these two reactions to find the stoichiometric factor that relates moles of
11. Use the equation: q = m(SH)ΔT to solve for the specific heat of the metal.
9. How many moles of NaOH would be needed to completely react with all of the excess HCl determined in problem 8?
3. How could a conductometric titration be used to determine the molarity of either reacting solutions, assuming the concentration of one solution was known? HINT: Consider the variables needed to calculate molarity, and how can these values be obtained from the titration. The symbol M stands for molarity with units of mol/L. Molarity is a measure of the concentration of a solution. If you knew the concentration of one of the solutions, the molarity could be found in this way. The concept plan would go as follows: Volume of Titrant (in liters) x Moles of Titrant (mol) = moles of the unknown, and then take Moles of the unknown / Liters of the unknown to get the Molarity of the unknown in mol/L. 4
It’s predicted that when adding the chemical substance into the water, energy will be released or absorbed, this will be observed by a temperature change, therefore, there would be an exothermic or endothermic reaction.
The literature value for the enthalpy change of the last reaction which was provided by our teacher is -97 kJ mol-1. Agreeing this value, our result can be considered accurate.
At the Left side of the equation, its show the energy (KJ/mole) taken in by the reaction,
This experiment was performed to determine the heat of neutralization between Hydrogen chloride (HCl) and Sodium hydroxide (NaOH). A temperature probe was used to measure the temperature of the reaction when the base (NaOH) was poured into the acid (HCl). The data was collected on logged on LoggerPro.
Notice that !:::"Q is positive when heat is added to the system. and!:::" W is positive when the system