Hooke's Law Experiment Report
Done by Yovaphine Wijaya – 11 Science 1
Aim
To investigate Hooke’s law for simple strings or rubber.
Hypothesis
The change in length of spring is directly proportional to the applied so that it will cause greater change in length of the spring for greater force applied. It is supported by the formula of force, F = kx, where F is the applied force, k is the spring constant of the spring, and x is the change in length or extension of the spring. Since the spring used is the same, the spring constant will always be the same for any value of force applied and extension of the spring.
Theory
The relationship between a load force and a light spring (F = kx) was the first determined by Robert Hooke in the 17th …show more content…
Data Processing
Table 6. Calculation table of the spring constant of spring for 30.00g ± 0.01g of load Trial  Force (N)  Final Length of Spring (m), Δl = 0.0005m  Extension (m), Δx = 0.0010m  Spring Constant of Spring (N/m), k  k  k ̅ (N/m)  (k  k ̅)2 (N/m)  1  0.29  0.200  0.060  4.9  1 x 102  1 x 104  2   0.200  0.060  4.9  1 x 102  1 x 104  3   0.198  0.058  5.1  2 x 101  3 x 102  4   0.201  0.061  4.8  9 x 102  8 x 103  5   0.200  0.060  4.9  1 x 102  1 x 104  6   0.198  0.058  5.1  2 x 101  3 x 102  7   0.200  0.060  4.9  1 x 102  1 x 104  8   0.202  0.062  4.7  2 x 101  3 x 102  9   0.200  0.060  4.9  1 x 102  1 x 104  10   0.200  0.060  4.9  1 x 102  1 x 104   TOTAL    49.1   9 x 102 
Example of the calculation of the spring constant of spring for 30.00g ± 0.01g of load, 1st trial
Extension x = x1 – x0 = (0.200m ± 0.0005m) – (0.140m ± 0.0005m) = 0.060m ± 0.0010m
Force
F = mg = (0.030kg ± 0.00001kg) x 9.8m/s2 = 0.294N = 0.29N (2 SF)
Spring constant of spring k = Fx = 0.294N0.060m =

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