Hydraulic Lab Report

The gradient in site 1 was 0, in site 2 it was 3 and in site 3 was 4. The hypothesis for this was the river gets steeper as you go downwards as the gradient decreases. My measurement is correct based on facts and my theory.

The parcel starts descending at 6000’ feet, the temperature at this height is 50.1 F, and is above the original LCL. The new LCL is at 6000’ feet as the parcel is starting its descent down the lee side of the mountain. The mixing ration to start to movement up the mountain was approx 18.9 g/kg and the descent capacity is approx 7.6 g/kg.

The ball now has kinetic energy. Kinetic energy like momentum in that it comes from the mass of the object and its velocity. Kinetic energy was transferred from the plunger to the ball just like momentum was but only if the collision was elastic. During and elastic collision kinetic energy is conserved. The balls kinetic energy is half of its momentum squared. This means the balls momentum is its mass multiplied by velocity, and then it is squared and divided by two. If the velocity or speed of the ball is reduced by one half then the overall kinetic energy is reduced by a factor of four (Kirkpatrick and Wheeler p.106)

1. What two parameters are responsible for creating the movement (filtration and reabsorption) of fluid across the capillary wall?

Total Cost EOQ = (F * T / Q) + (H * Q / 2) where Q = 5,656.85 kg

ee = (dQe/dPe)*(Pe/Qe) ; dQe/dPe is the coefficient of price in the approximated demand equation.

Independent Variable: The cell and its volume, surface area, and the water potential of the internal cell and its environment

baseline (see Figure 9.4 on page 288 for help). If the solvent traveled 57 mm

Provide formulas in cells M2 through M8 that square the differences found in cells L2

When the environment is in equilibrium, it has a minimum potential energy (mgz) and a zero speed (v=0), so kinetic and potential energy changes are omitted and it reduced to Eq. 3.

The experiment performed was Experiment IV: Fluid Flow Meters and Tray Hydraullics. The group was composed of Alex Long, Khanh Ho, Tricia Heitmann and myself. The first day of

4. The flow velocity increases as the flow gets closer to the barrier wall and reduces as it moves away from the wall. This is because as the flow rate is constant (Conservation of mass) while the area of the flow cross section decreases when it gets closer to the barrier wall, the flow velocity increases. This is best understood by referring to the continuity equation,

3. Calculate the total heat released in each reaction, assuming that the specific heat of the solution is the same as for pure water (4.18J/gK). Use q=mcΔT. Show work here and record your answer in Data Table 2.

In this experiment, three variable flow meters are used to alter the flowrate. Changes in pressure drop due to the change in flowrate are then observed from the three pressure gauges that can measure pressure at different range and recorded. The shift from laminar flow to turbulent flow is seen from the results recorded, but it is observed more clearly from the water-soluble dye experiment that was carried out by the demonstrator. Laminar flow turns to be turbulent when the Reynolds Number goes above a certain value, around 2000.

2) Derive equations for the mass (Mtheoretical) that balances the hydrostatic force for the fully submerged case. (i.e. h greater than a) Mtheoretical = f(a, b, g, k, h, L, γw)