Identification of Unknown Ketones Essay

1152 WordsOct 27, 20115 Pages
Purpose: The purpose of this experiment was to identify one ketone with Thin Layer Chromatography and one using NMR spectrometry. We will do this by making 2, 4 a DNPH derivative and checking the melting points. Theory: By Using specific methods of compounds detection, we can match an unknown compound with a known compound because similar compounds will display similar characteristics. In this experiment, identifications of the unknown ketone was accomplished using thin layer chromatography, melting point, and NMR spectrometry. Thin layer chromatography is very quick but sensitive way of determining the components of a mixture or a specific compound from a list of knowns. This method is the one which was utilized in the…show more content…
Next, I observed my Proton NMR which had only one peak. The multiplicity is six. Therefore, I have six hydrogens. Using this information, I was able to conclude that my unknown is 2-propanone. Discussion/Conclusion This experiment was done to identify one ketone with Thin Layer Chromatography and one using nuclear magnetic resonance spectrometry. When using Thin Layer Chromatography, I was able to determine my unknown by observing my slides and seeing that the spots of my unknown are most like those of 2-heptanone in height and size. Furthermore, I calculated my Rf values and determined that my Rf value of Unknown K (.5) was most near my Rf value of 2-heptanone (.51). Finally, comparing the derivative melting points of these two substances confirms that 2-heptanone is my unknown. The derivative melting point of 2-heptanone is 89 while my unknown was 87. When using nuclear magnetic resonance spectrometry, I had unknown A. With this unknown, I had two peaks on my CNMR which told me I had one carbon on both sides of the line symmetry. Also, on my HNMR I had one peak with a multiplicity of six, therefore, I had six hydrogens. Using this information I was able to conclude that my unknown as was 2-propanone. Furthermore, in this experiment we learned that NMR takes advantage of the magnetic properties of the 1H and 13C nuclei. We are not concerned with 12C because it does not have a magnetic
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