# Essay about Ilab Week 6 Devry

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Statistics – Lab #6

Name:__________

Statistical Concepts: * Data Simulation * Discrete Probability Distribution * Confidence Intervals

Calculations for a set of variables

Calculating Descriptive Statistics

Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum
Mean 20 0 3.560 0.106 0.476 2.600 3.225 3.550 3.775 4.500
Median 20 0 3.600 0.169 0.754 2.000 3.000 3.500 4.000 5.000

Calculating Confidence Intervals for one Variable

Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum
Mean 20 0 3.560 0.106 0.476 2.600 3.225 3.550 3.775 4.500
Median 20 0 3.600
Is this estimate centered about the parameter of interest (the parameter of interest is the answer for the mean in question 2)?

The mean for the median column of the worksheet is 3.6Yes, the estimate is centered about the parameter of interest. |

5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?

Standard Deviation for the mean column is 0.476Standard Deviation for the median column is 0.754Standard deviation for the mean column has least variability |

6. Based on questions 3, 4, and 5 is the mean or median a better estimate for the parameter of interest? Explain your reasoning.

Mean is the better estimate for the parameter of interest. The mean is more centered with least variability. |

7. Give and interpret the 95% confidence interval for the hours of sleep a student gets.

One-Sample T: Sleep Variable N Mean StDev SE Mean 95% CISleep 20 6.950 1.572 0.352 (6.214, 7.686)95% of students get between 6.2 hour to 7.69 hour of sleep. |

8. Give and interpret the 99% confidence interval for the hours of sleep a student gets.

One-Sample T: Sleep Variable N Mean StDev SE Mean 99% CISleep 20 6.950 1.572 0.352 (5.944, 7.956) 99% of students get between 5.9 hour to 7.95 hour of sleep. |

9. Compare the 95% and 99% confidence intervals for the hours of sleep a student gets. Explain