preview

Improving Quaity of Services in KENIKA Enterprises Essay

Satisfactory Essays

1. Objective(s):
This study aims to apply basic knowledge in Advanced Operations Research through the use of Queuing system
2. Intended Learning Outcomes (ILOs):
The students shall be able to:
2.1 Analyze the existing operations of the selected company
2.2 Apply Advanced Operations Research techniques to the identified problem(s) or goal(s).
2.3 Communicate problems and solutions through written and oral presentation
.
3. Discussion
This paper is a Case study on how principles of Operations Research will be applied to improve the Quality of Service in Material receiving Area in KENIKA Enterprises. In KENIKA Enterprises in Pampanga, all vehicles with raw materials comes to front gate. These trucks are tested for presence of …show more content…

Procedure
1. KENIKA Enterprises Materials Receiving System
2. Eliminate the queuing time in all server in KENIKA
3. 37 tucks were accommodated in 8 hours of service
4. The queuing system theory

6. Data and Results: First server gate a accommodated 37 trucks it took 14.3% delay, Second server which is the queue between CRS and Security took 6.1% delay, Security checking took 0.3% delay, Weightment took 30.9% delay, Movement between store took 28.8%, Unloading materials in store took 10.5% delay and Exit weightment and Checking took 9.1%.
TREATMENT OF DATA
arrival rate 
service rate

Arrival time = 1/arrival rate
Service time = 1/service rate

Inter-arrival time between services
Inter-arrival time between services are 1.144, .488, .024, 2.472, 2.304, .84, and .728
The service time for the channels are:
 =1/1.144 = 0.87
 =1/.488 = 2.05
 =1/.024 = 41.67
 =1/ 2.472 = 0.40
 =1/ 2.304 = 0.43
 =1/ .84 = 1.19
 =1/ .728 = 1.37
Arrival time for the channels are:
1/ 1.144 = 0.87
1/ 0.656= 1.52
1/ 0.464 = 2.155
1/ 2.448 = 0.408
1/ 0.168= 5.95
1/ 0.68 = 1.464
1/0.112= 8.92
We can see that the longest service time is the lowest in arrival rate that is the server or channel 4.

Additional formulas used in queuing systems
Response time

Mean response time R E(r) = (

Variance of the response

Get Access