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Lab Report On Carbonate

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To find moles of carbonate we needed to first determine the total alkalinity with HCL 0.1 M as the titrant, meaning that the end point indicates the complete conversion of bicarbonate and carbonate to carbonic acid. Indicator bromocresol green (BG) was used to observe this end point since the range at which this end point will occur will exist in the slightly more acidic portion of the pH scale covered by BG. This total alkalinity is given by (2[CO32-]+[HCO3-] )=VHCl[HCl] where VHCL is the volume from our standard HCl used in titration. Afterwards, we can determine the concentration of bicarbonate by performing the steps outlined in the procedure to begin converting the bicarbonate to carbonate, precipitating this carbonate, and thus …show more content…

Discussion
We obtained a composition of 58 (±5.1) wt% Na2CO3 and 42 (±8.3) wt% NaHCO3 for the unknown solid analyzed in this experiment. Although the accuracy of these results cannot be fully evaluated, since we do not have a known composition concentration to compare, we must assume that there was some contribution of error, especially given the somewhat large errors observed. One possible source is a miscalculation of the volumes or concentrations obtained from the results due to exposure of CO2 in our titrants and solutions which, as discussed in the previous lab report, can make our solution more acidic than what the nature of the experiment requires.2 Therefore, different volumes of standard HCl would be necessary for titration. A simple solution for this issue would have been boiling the distilled water to expel carbon dioxide from the stock solutions. Additionally, the stock solutions may also be responsible for some of this error. Besides having stock solutions available for the entire class, which may cause cross contamination and mishandling of the stock solutions, the stock solution needed to be replenished multiple times, thus providing the possibility of preparing a solution with a different molarity. Moreover, at one point all 0.1 M NaOH had been expended, and the only option available was to use a solution of 0.08 M NaOH for further experiments. This was

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