Decent Essays
The Math of Stunting

The physical nature of the sport cheerleading, demands a grasp on the knowledge of how both the forces that are exerted and those one experiences will affect one’s performance in a stunt or trick. Physics and mathematics can be found everywhere in cheerleading: 8-counts direct a dancing routine, weight distribution determines a three-level pyramid. The highly organized nature of cheerleading, with all of its formations and different groupings of, in Columbia River’s case, members based on their “job” in that stunt – back spot, base, or flyer – can hardly be removed from the concepts of math. Rather, a cheerleader with a true knowledge of physics and mathematics will undoubtedly be more successful in their happenings –
The flyer begins this move with their center of gravity 4 feet above the ground. One is thrown with an initial vertical velocity of 30 feet per second.

1. Will the flyer’s center of gravity ever reach 20 feet?
2. For the flyer to have her center of gravity reach 25 feet, what does the initial velocity need to be?
A quadratic function has the form: y = 〖ax〗^2+ bx + c
The movement that makes this object is a uniformly varied movement, because it is subject to the acceleration of gravity. In these types of movement, the position of the body with respect to time, is described by a quadratic function of the form: h = ± (1/2) 〖gt〗^2+ V_0 t+ h_0
The ± signs correspond to the acceleration of gravity and the sign is chosen according to the direction of motion; if the motion is upward the value (-g) is taken and if it is down, the value (+g) is taken.
Comparing these equations, we see that both have the same structure:
The variable y represents the height h, and the variable x represents time t; also the coefficients a, b and c have the values: a = ± (1/2) g, b = V_0 , c =