995 Words4 Pages

UNIVERSITI TUNKU ABDUL RAHMAN
|Centre |: Centre for Foundation Studies (CFS) |Unit Code |: FHSC1014 |
|Course |: Foundation in Science |Unit Title |: Mechanics |
|Year/ Trimester |: Year 1 / Trimester 1 |Lecturer | |
|Session |: 201605 | | |
Additional Tutorial 2: Vector and translational kinematics.
1. Find the x and y-components of: (a) a displacement of 200*…show more content…*

Tutorial 2: Vector and translational kinematics. 1. (a) Dx = 200 cos 30.0o = 173 km Dy = 200 sin 30.0o = 100 km (b) vx = 40.0 cos 120o = -20.0 km/h vy = 40.0 sin 120o = +34.6 km/h (c) Fx = 50.0 cos 330o = 43.3 N; Fy = 50.0 sin 330o = -25.0 N 2. [pic] | Vector |x-component |y-component | |F1 |-(21.0) sin30.0o = -10.5 N |+(21.0) cos30.0o = +18.2 N | |F2 |+15.0 N |0 N | |F3 |-(-10.5+15.0) = -4.5 N |-(18.2+0) = -18.2 N | [pic] [pic] 3. Wx = 200 sin 300; Wx = 100 N, down the plane. Wy = 200 cos 300; Wy = 173 N, normal to the plane. 4. The triple jump consists of a double jump in one direction, followed by a perpendicular single jump, which we can represent with displacement vectors J and K and D = J + K. J = 4d and K = 2d where [pic]. [pic] [pic] 5. (a) [pic] (b) When the faster car has a 15.0 min lead, it is ahead by a distance equal to that traveled by the slower car in a time of 15.0 min. [pic] The faster car pulls ahead of the slower car at a rate of

Tutorial 2: Vector and translational kinematics. 1. (a) Dx = 200 cos 30.0o = 173 km Dy = 200 sin 30.0o = 100 km (b) vx = 40.0 cos 120o = -20.0 km/h vy = 40.0 sin 120o = +34.6 km/h (c) Fx = 50.0 cos 330o = 43.3 N; Fy = 50.0 sin 330o = -25.0 N 2. [pic] | Vector |x-component |y-component | |F1 |-(21.0) sin30.0o = -10.5 N |+(21.0) cos30.0o = +18.2 N | |F2 |+15.0 N |0 N | |F3 |-(-10.5+15.0) = -4.5 N |-(18.2+0) = -18.2 N | [pic] [pic] 3. Wx = 200 sin 300; Wx = 100 N, down the plane. Wy = 200 cos 300; Wy = 173 N, normal to the plane. 4. The triple jump consists of a double jump in one direction, followed by a perpendicular single jump, which we can represent with displacement vectors J and K and D = J + K. J = 4d and K = 2d where [pic]. [pic] [pic] 5. (a) [pic] (b) When the faster car has a 15.0 min lead, it is ahead by a distance equal to that traveled by the slower car in a time of 15.0 min. [pic] The faster car pulls ahead of the slower car at a rate of

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