Measure the mass and calculate the density of the magnet using the correct significant figures and units. Show work for full credit. (2 points)
c. A lab exercise in BIO156 required 300 ml of water that was poured from a two-liter container. How many milliliters were left in the original container? (4 points)
To exemplify, when we were measuring the initial mass for the potato to be put in the 0.4M solution, 25.60 g came up the most, however, other masses between 25g to 27 grams came as well. Relating to this, for the final mass of 0.8M first appeared as 20.47 g but then it kept on changing from 21 to 23 g. Nevertheless, we guessed this may have been more accurate because it was the one sensed most immediately and on top of that we were confused on which one to pick. Therefore, when just had to pick the number that showed up the most often or first appeared at times during the process. Hence, our initial and final masses of the potato may have been slightly off.
E[Rp ] = (1 − wTb )RF,b + wTb E[RTb ] = (1 − 1.1735) × 0.02 + 1.1735 × 0.04386 = 4.80%.
Complete the calculations below using this data. Show all of your work and clearly label each of your calculations.
For MR = 0, Qw= 3498.65/0.3294 = 10621.28 and Qe= 2719.8714/0.065 = 41844.18. Hence Q = 52465.46.
by 1, and then the new value is used in the expression in which it appears. For example,
A salt concentration of 1562 ppm is equivalent to an electrical conductivity of how many dS/m?
However, it is fair to provide lesser coefficient to M3, due to its relation with the original data. This means, the coefficient of M3 must be lesser than the first or second order Matrix. Therefore, the coefficient of M3 is 0.4, which is smaller than any of M or M2.
15c (50) = 750c for classic 12m (40) = 480m which equals 750 + 480 = 1230. We can fill the order.
To increase the value of the variable, you may enter this statement on the command
Answer: D DM 13.00 + DL 55.00 + V OH 1.00 + F OH 15.00 = 84.00
I substitute the variables with the values 13.5 and 2. The 2 is for the
The receiving overhead per unit of Pumps produced = (0.19 X 20,000)/ 12500 = $0.3
The receiving overhead per unit of Pumps produced = (0.19 X 20,000)/ 12500 = $0.3