Newton 's Second Law And The Relationship

45. You just removed 60,000 grams of 5.56 ammo from the stockpile of 167 kilograms. How manykilograms remain?

0.53×2×180.192 g = 191gms 5.

You will add both amounts together (0.5 to 0.4) in order to get pounds for the ES which is 0.9

4. Connect the Newton Scale to the cart and then drag the cart up the ramp, across the 30cm difference at a steady rate.

5. Tie one end of the 60-cm string to the mass. Place the mass on a table below

First measure the amount of time it takes the MHC to cross the 30 cm distance with nothing in the crate (control). As soon as the MHC begins to move from the end of the container towards the fish flakes, start your stopwatch. If it pauses, gently tap it on the back or legs to get it to continue moving. As soon as it arrives at the location of the fish flakes or the end of the 30 cm walk, stop the stopwatch and record the time.

Place the object of your choosing on the triple beam balance's plate. 3. Use the weights to get the other side of the scale on zero to get the mass. 4. Next, place the object in a graduated cylinder filled with

Now that we have our basket, we can track prices on the items in the cart and see how much it all costs.

Seven various household objects were chosen to measure using a digital gram scale. Each object’s mass was estimated by lab students and recorded in data table 4. A quarter, ball point pen, rubber bulb, large paper clip, green crayon, house key and a copper penny masses were estimated and recorded in data table 4. Each object was placed on the scale individually and its actual measurement was recorded in data table 4. As we started estimating the household objects we were often not correct in our estimations. As we measured more and more objects, we got better in our estimations by comparing objects with known masses and comparing them with the unknown

1. Started with a similar mass of M=500g at a distance l, along the ruler from the pivot.

We experienced the effects of pushes and pulls in Activity 2 when we played around with the carts on the track. We noticed in experiment #1 that it doesn’t matter if you push or pull the cart to get it moving. We were also able to identify that when we gave the cart a second push it would speed up. In Activity 3 we messed around with the friction pads on the carts to show that the cart will slow down when there is a force acting in the opposite direction. When we tapped the cart the other way, there was also either a change in directions or a decrease in speed.

A smart pulley is clamped onto the side of the table and connected to a computer to sync with Capstone. In Capstone, select the device as “Photogate with Pulley.” Set up a position vs time graph to record data for. Attach a string to the cart, over the smart pulley, and latch it onto a 5g hook to the side of the table. Obtain four weights: two 20g, one 50g, and one 100g. While keeping the cart in place, keep one 20g weight on the hook and the remainder in the cart. Start recording data from the smart pulley and release the cart so that it will slowly slide towards the edge of the table. Grab the cart before it hits the pulley and stop recording data. Reset the cart's position to 50 cm away from the edge. Repeat this process for the following masses on the hook: 40g (two 20g weights), 70g (one 20g weight and a 50g weight), 100g (just the 100g weight), and 170g (one 20g, 50g, and 100g). Keep the remainder weights on the cart. Be careful with the cart at higher masses on the hook, as it will move quickly. Once the trials are completed, create quadratic fits for the recorded data on Capstone. Make sure to remove unwanted data, such as the initial motionless state of the cart and the adrupt halt of its motion. The acceleration of the system is two times the value of the A constant in the curve fit; record this and do this for all trials.

4. Thread a length of ticker-tape, about the same length as the cart’s distance down the path, through the ticker timer. Stick the end of the tape to the trolley.

Step 9: Because we measured the lengths in centimeters rather than meters, we need to calculate are ‘g’ value into m/s2 so we can compare it to the SI unit for acceleration due to gravity. (Eg. 981.4/100 = 9.81 m/s2)

Theoretically if there were no resistant (e.g air resistance, friction ETC) a down falling body on Earth would accelerate at the rate of 9.8 m/s^2, this is known as the gravitational acceleration. Theoretically the force of the downfall and acceleration for 500 gram would be 9.8 m/s^2 x 0.5 kg = 4.9 N. However in this prac as the force is greatly reduced by the resistant forces such as friction between the wheel and the table or the air resistant faced by the trolley and weight, the total amount of force was reduced.