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Newton's Law Lab Report

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1. INTRODUCTION
In this experiment we learned Newton's Law. Newton's first law stated an object at rest stays at rest and an object in motion keeps moving with a constant velocity until/unless a net external force. Newton's second law stated a equation F ⃗=ma ⃗ and the third law stated for every action there is an equal and opposite reaction. We have also learned steps such as, draw free body diagram with labels, write Newton's equations and solve the equation in order to find the result. The purpose of this experiment is to study the relationship between force and acceleration using a linear track and the Atwood's machine. Hypothesis in this experiment is to see if this equation F ⃗=ma ⃗ is correct because when deriving the equation to find …show more content…

2.
Trial 1 m_1=0.100kg m_2=0.110kg a_e=0.31m/s^2 a_t=((m_2-m_1)/(m_2+m_1 ))g a_t=((0.110kg-0.100kg)/(0.110kg+0.100kg))×9.18 a_t=0.44m/s^2 percent error= |E-A|/A×100% percent error= |0.31m/s^2-0.44m/s^2 |/(0.44m/s^2 )×100% percent error= 29.8%
Trial 2 m_1=0.095kg m_2=0.115kg a_e=0.81m/s^2 a_t=((m_2-m_1)/(m_2+m_1 ))g a_t=((0.115kg-0.095kg)/(0.115kg+0.095kg))×9.18 a_t=0.87m/s^2 percent error= |E-A|/A×100% percent error= |0.81m/s^2-0.87m/s^2 |/(0.87m/s^2 )×100% percent error= 6.9%
Trial 3 m_1=0.085kg m_2=0.125kg a_e=1.64m/s^2 a_t=((m_2-m_1)/(m_2+m_1 ))g a_t=((0.125kg-0.085kg)/(0.125kg+0.085kg))×9.18 a_t=1.75m/s^2 percent error= |E-A|/A×100% percent error= |1.64m/s^2-1.75m/s^2 |/(1.75m/s^2 )×100% percent error=

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