5471 Words22 Pages

Chapter 13: Chi-Square Applications
SHORT ANSWER
1. When samples of size n are drawn from a normal population, the chi-square distribution is the sampling distribution of = ____________________, where s2 and are the sample and population variances, respectively.
ANS:
PTS: 1 OBJ: Section 13.2
2. Find the chi-square value for each of the right-tail areas below, given that the degrees of freedom are 7:
A) 0.95 ____________________
B) 0.01 ____________________
C) 0.025 ____________________
D) 0.05 ____________________
ANS:
2.167; 18.475; 16.013; 14.067
PTS: 1 OBJ: Section 13.2
3. Find the chi-square value for each of the four degrees of freedom below, given that the area to the left of a chi-square value is 0.05.
A) 2*…show more content…*

NARREND 10. At the 0.05 significance level, what is the appropriate table value? ANS: Critical Value2(0.05, 3) = 7.815 PTS: 1 OBJ: Section 13.3 11. What is the conclusion? ANS: Do not reject H0; there is no evidence to suggest the present accommodation is different from the national one. PTS: 1 OBJ: Section 13.3 12. Assuming that there is only one category with an expected frequency less than five, what is the appropriate table value for the 0.05 significance level? ANS: Critical Value2(0.05, 4) = 9.488 PTS: 1 OBJ: Section 13.3 NARRBEGIN: Number of sales A salesperson makes five calls per day. A sample of 200 days gives the frequencies of sales volumes listed below NARREND 13. Assume the population is a binomial distribution with a probability of purchase equal to 0.50. Compute the expected frequencies (Ej) for the number of sales by using the binomial tables. Combine if necessary to satisfy the rules of five. ANS: x Oj p(x) Ej 0 10 .0313 6.26 1 38 .1562 31.24 2 69 .3125 62.50 3 63 .3125 62.50 4 18 .1562 31.24 5 2 .0313 6.26 TOTAL 200 1.00 200 PTS: 1 OBJ: Section 13.3 14. Should the assumption of a binomial distribution with a probability of purchase equal to 0.50 be rejected at the 5% significance level? Hypotheses: ____________________ Test statistic = ____________________ Critical Value = ____________________ Conclusion: ____________________________

NARREND 10. At the 0.05 significance level, what is the appropriate table value? ANS: Critical Value2(0.05, 3) = 7.815 PTS: 1 OBJ: Section 13.3 11. What is the conclusion? ANS: Do not reject H0; there is no evidence to suggest the present accommodation is different from the national one. PTS: 1 OBJ: Section 13.3 12. Assuming that there is only one category with an expected frequency less than five, what is the appropriate table value for the 0.05 significance level? ANS: Critical Value2(0.05, 4) = 9.488 PTS: 1 OBJ: Section 13.3 NARRBEGIN: Number of sales A salesperson makes five calls per day. A sample of 200 days gives the frequencies of sales volumes listed below NARREND 13. Assume the population is a binomial distribution with a probability of purchase equal to 0.50. Compute the expected frequencies (Ej) for the number of sales by using the binomial tables. Combine if necessary to satisfy the rules of five. ANS: x Oj p(x) Ej 0 10 .0313 6.26 1 38 .1562 31.24 2 69 .3125 62.50 3 63 .3125 62.50 4 18 .1562 31.24 5 2 .0313 6.26 TOTAL 200 1.00 200 PTS: 1 OBJ: Section 13.3 14. Should the assumption of a binomial distribution with a probability of purchase equal to 0.50 be rejected at the 5% significance level? Hypotheses: ____________________ Test statistic = ____________________ Critical Value = ____________________ Conclusion: ____________________________

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