Nt1310 Unit 4

We have simulated another network having 30 numbers of nodes. The simulation is made using the same platform used for network 1. This simulation is done taking node 1 as a source and node 28 as destination. The optimal path obtained in this simulation is 1-23-13-28, in which data rate is 0.47 kbps. The second optimal path is 1-17-28, in which data rate is 0.35 kbps. The simulated results are summarized here in

(ii) All trains are assumed to follow the same speed between two consecutive stations, so the pure running time

To ensure QoS in our proposed algorithm we calculate the utility of a node e.g. $node_i$ as the summation of remaining CPU cycle ($R_{CPU_i}$), remaining memory in that node ($R_{mem_i}$), remaining bandwidth available for that node ($R_{bw_i}$), remaining data reside in the buffer to transmit ($R_{data_i}$), data rate ($Data_{rate_i}$) and priority of data to be transmitted $Pri_{data_i}$.

Assume a 6,000-km-long copper transatlantic cable in which the propagation speed of the electric signal is 222,000 km/s. A delivery time of approximately 80 ms is measured for an 8 kB message. Estimate the bit rate of this cable (in bits/s) ?

I'm using an approximation on the times, since I'm not completely sure what they are.

This table below shows the original times converted into seconds, for the purpose of not having to round numbers and equal calculations.

For Patton-Fuller to fully utilize their potential networking power, the following protocols should be utilized. Patton-Fuller should utilize a Gigabyte Ethernet Network for all its hardwired LAN connections. Gigabyte Ethernet is part of the family of Ethernet computer networking and communication standards. The Gigabit Ethernet standard supports a theoretic data rate of 1 gigabit per second. Gigabyte Ethernet networks are connected by CAT5e and CAT6 cabling (Gigabit Ethernet, 2013). The Gigabyte Ethernet network should be accomplished by using layer 3 switch. A layer 3 switch is a high-performance device for network routing. Layer 3 switches actually differ very little from routers. A Layer 3 switch can support the same routing protocols as network routers do. Both inspect incoming packets and make dynamic routing decisions based on the source and destination addresses inside. Layer 3 switches improve on the performance of routers

30. How many pairs of wires are crossed in a crossover cable that will work on a 100BaseT network? On a 1000BaseT network?

The following case study is used to illustrate the process required for designing a redundant switched network. This case study presents a scenario in which XYZ Insurance Company has hired a Network Consultant Group to design their network. In order to help you organize this project, the scenario has been divided into phases listing the requirements for each task.

Both circuit-switching and packet-switching are methods of data communication between two parties. In circuit switching, both parties agree on a specific path which the data will travel along while the connection is open using a resource optimization algorithm before the transmission begins. The route is used exclusively for the entire session and only released when the session is terminated.

How the data was collected was using a stopwatch at 00:00 (zero minutes and zero seconds). The stopwatch began and we waited for the first customer to arrive. The first customer arrived 00:36 or 36 seconds after the stopwatch began to run, hence that is their inter-arrival time. Customer 1 departed at 1:18 from when the stopwatch ran. By taking the difference between the departure clock time and arrival clock time, service time was calculated. This was done for all 15 customers. Arrival times and departure timesare in clock time because we observed their arrivals and departures by viewing a stopwatch. The final clock time noted is 11:36 (so 11 minutes and 36 seconds from when the clock first began) and that is the same time the final customer (customer 15) departed.

the time in which the first person/object had move, it will not reach by the second person/object because of n time and n distance between the two.

As Cp and Cpk is almost same & greater than 1, the process distribution curve is at the center and capable of meeing the target time of 20 min.

time the third and the rest of the blocks are processing the applied inputs (time 129.99 ns).

However, the present digital to analog converters (DAC)/ (ADC) can only support upto 6 GHz bandwidth. It became a challenge to realize 100 Gb/s transmission in a cost effective manner. But, recently DAC/ADC realized more than 30 GS/s with more than a 20 GHz analog bandwidth. This can support a 100 Gb/s transmission.