Observations of Chemical Changes

1. The first experiment is Preparation of a Cobalt Amine Bromide Product ; Synthesis #3 was used to create the compound. Added 5 grams of cobalt carbonate to 20 mL of hrdrobromic acid in a beaker. Noticied a slight color change to dark purple. Solution frothed after it settled I mixed in 15mL water and

When observed, the water was a blue-green all the way through. This is because the seal was more than likely not tight enough around the test tube, letting oxygen into the tube, which caused the color to change.

When combined Sodium Bicarbonate and Hydrochloric Acid, Carbon Dioxide is produced. The two chemicals do not undergo a change in color but a chemical change when CO2 is produced.

When the tip of the rod touched the pH paper, the color of the pH paper became blue.

The Vitamin C turned to a red/orange color with no physical/chemical reaction. For the salt the solution turned to an orange color with no physical/chemical reaction. With the Alka-Seltzer, the solution turned to a brown color with no reaction as well. Last but not least, the Baking soda turned to an orange/brown color with no reaction.

The primary goal of this laboratory is to correctly identify an unknown substance. To achieve this task, one may use various tests that reveal both chemical and physical properties of a substance. By comparing the results of a known substance and the unknown substance, one may eliminate alternative possibilities and more accurately predict the undisclosed compound. Furthermore, by performing these tests, data can be collected and verified regarding chemical and physical properties of the unknown. Understanding the chemical properties of a known substance aids one’s understanding of the unknown based on comparative analysis of the results of the tests.

3.What was your prediction about the results of each factor tested in your two lab procedures? Explain your predictions based on your knowledge of the dissolving process, collision theory, and reaction rates.

To begin, in order for the compounds to react they will be dissolved in water and sulfuric acid will be added. The addition of sulfuric acid will then generate hydrobromic acid, an important product in the reaction mixture. The hydrobromic acid will react with the 1-butanol when heat is added to the flask during refluxing. Refluxing is the heating of a flask to boiling and then allowing

Heavy precipitate emerged immediately and solution turned white in color; solution then became opaque and turned light, bright blue in color.

Discussion The purpose of this lab was to measure the mass of a solid reactant, in this case, NaHCO3, which is also known as baking soda, and to find the mass of the solid product NaCl (salt) as well. From there, the masses were to be converted into moles and created into ratios that showed the relationship between the reactants and products. That information was then compared to the theoretical data in order to check its accuracy and reveal the significance of mole ratios in chemical reactions.. During the experiment, hydrochloric acid (HCl) was added to the baking soda in order to begin the reaction.

Copper(II) chloride solution was the lightest shade of blue and Cobalt chloride solution was the darkest.

B )The way I will gauge the amount of each hued compound was in the blend is by utilizing paper chromatography, the most remote the shading goes on the paper is the littlest and the closest is the higher sum.

The lower the metal is in the group the faster it will react with water. This was seen to be true for both groups one and two. In all cases the metals reacted to form Hydrogen Gas ad a solution that was alkaline. Down the group the electronegativity decreases which results in a metal element losing its valance electrons more easily and hence reacting more

For each of the combinations of chemicals below put 2 drops of each in their own well in the 96-well plate. Making sure to place only 2 drops of the first chemical then

D. The second unknown solution turned a dark blue/purple color which I believe to be negative.