preview

Physics : Calculus Ia Section 2

Satisfactory Essays

Calculus IA Section 2, Part B 4. A particle moves along the x-axis with position at time t given by x (t) = e-t sin t for 0 ≤ t ≤ 2π. (a) Find the time t at which the particle is farthest to the left. Justify your answer. Answer: x’ (t) =e-t sin t + e-t cos t = e¬¬¬-t (cos t – sin t); x’ (t) = 0 when cos t = sin t. Therefore, x’ (t) = 0 on 0 ≤ t ≤ 2 π for t = π/4 and t = 5 π/4. For the absolute minimum are at t = 0, π/4, 5 π/4 and 2 π. The particle is farthest to the left when t = 5 π/4. (b) Find the value of the constant A for which x (t) satisfies the equation Ax’’ (t) + x’ (t) + x (t) = 0 for 0 < t < 2 π. Answer: x’ (t) = -e-t (cos t – sin t) + e-t (-sin t – cos t) = -2e-t cos t ; Ax’’(t) + x’ (t) + x (t) = A (-2e-t cos t) + e-t (cos t – sin t) + e-t sin t = (-2A + 1) e-t cos t = 0; therefore, A = 1/2 5. The volume of a spherical hot air balloon expands as the air inside the balloon is heated. The radius of the balloon, in feet, is modeled by a twice-differentiable function r of time t, where t is measured in minutes. For 0 < t < 12, the graph of r is concave down. The table above gives selected value of the rate of change, r’ (t), of the radius of the balloon over the time interval 0 < t < 12. The radius of the balloon is 30 feet when t=5. (a) Estimate the radius of the balloon when t = 5.4 using the tangent line approximation at t =5. Is your estimate greater than less than the true value? Give a reason for your answer. Answer: r (5.4) = r (5) (t) = 30 + 2 (0.4) =

Get Access