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Polar Covalent Bonding Lab Report

Decent Essays
Claim: Through a experimental procedure #1 was concluded to be metallic, #2 to be polar covalent bonding, and #7 to be polar covalent.

Reasoning:
The main motive of the lab was determine the unknown substances identity by its tested characteristics. Considering the results of the lab, substance #1 would be a metal since it has metallic characteristics. A few metallic characteristics are a high melting point, insoluble in water, and a good conductor of a solid and liquid. All of these characteristic are cohesive with the observations made. It had a melting point above 500°C, it did not dissolve in water, and it was a good conductor as a solid and a liquid. It also looked and felt similar to what other metals do. Since it did not dissolve in
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The heat overcame the hydrogen bondings between 100°C to 500°C and the white powder melted. Other characteristics would be solubility in water which substance #2 preformed. Polar substances dissolve in water; “like” dissolves “like”. In addition substance #2 did not dissolve hexane. Hexane is a non polar substance and if it did not dissolve in hexane it was most likely not non polar. Moreover, substance #7 was polar covalent with hydrogen bonds and dipole-dipole bonds. Substance #7 is not ionic because it did not conduct in water and it did not conduct electricity while in water. Similar to adipic acid it dissolved in the ethyl alcohol. As stated before, “like” dissolves “like” so since ethyl alcohol is polar, substance #7 would also have to be polar. In general polar substance tend to have a higher melting point which substance #7 had. It melted between 100°C and 500°C. Some sources of error would be the mixture of substance when determining the melting point over the boiling water. The mixing of the substances would have altered the data. Another source of error would be using too much substance in the dish when checking for solubility. Too much substance would have altered
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