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Poverty Case Study

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1a. religion | Freq. Percent Cum. ------------+----------------------------------- 0 | 1,821 31.35 31.35 1 | 1,617 27.84 59.19 2 | 1,422 24.48 83.68 3 | 165 2.84 86.52 4 | 125 2.15 88.67 5 | 53 0.91 89.58 6 | 605 10.42 100.00 ------------+----------------------------------- Total | 5,808 100.00 Percentage of Catholics: 24.84% 90%: = 24.840.92 = 23.92 to 25.76 95%: = 24.841.10 = 23.74 to 25.94 99%: = 24.841.44 = 23.40 to 26.28 1b. The 90% confidence interval is the narrowest and the 99% confidence…show more content…
3a. Figure 7.2 depicts a normal sampling distribution, which is being used to calculate a difference of proportions test of significance. The image shows the calculation of a confidence interval that is 1.96 times the standard error, i.e. 95 percent confidence. It also shows how the application of this confidence interval about the mean creates two legs outside of the mean, which, in this case, each represent 2.5 percent confidence respectively. 3b. Percentage of Republicans in 1984: 44.22% Percentage of Republicans in 1992: 41.86% = = -0.99 to 5.71 3c. Based on this equation, we can conclude that we cannot eliminate the possibility that there was no significant change in the number of Republicans from 1984 to 1992. This is because the 95% confidence interval includes within it the result we would expect to see if the null hypothesis were true, i.e. if there was no difference between the number of Republicans in 1984 and 1992. In this case, the null hypothesis is that - = 0 and 0 falls within the range of -0.99 to 5.71. Therefore, there is a greater than 5% chance that the difference is 0 and thus the null hypothesis cannot be eliminated. 4a. According to the stated hypothesis, Bush would have received half of Perot’s voters (129), bringing Bush’s number of voters from 477 to 606. However, the other half of Perot’s voters would not have voted, thus lowering the total percentage of voters (i.e. the denominator) from 1335 to
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