Problems on Physics

(.1063 KIO31) (1 mol KIO214 g) x 6 mol S2O41 mol KIO= .00298.04150= .259 M

because each of the objects displaced the water by 1 mL, their mass over that mL is their density.

45. You just removed 60,000 grams of 5.56 ammo from the stockpile of 167 kilograms. How manykilograms remain?

The calculated volume used the length x the width x the height to get its volume. I feel the measurement method would be more accurate as it is using exact measurements. Archimedes Principal could possibly be flawed if not done exactly right.

Can I apply this somehow to volume? Well at standard temperature and pressure (STP) a mole of a gas will occupy 22.4 liters. So If we keep our units straight we should be able calculate a given volume of gas from moles. Check it out…… http://www.sciencegeek.net/Chemistry/Video/Unit4/GMV4.shtml

Enter the precise mass in GRAMS of the potassium iodate used to prepare your primary standard solution.

c. A lab exercise in BIO156 required 300 ml of water that was poured from a two-liter container. How many milliliters were left in the original container? (4 points)

4. A solid block of exactly 100.0 cm3 has a mass of 153.6 g. Determine its density. Will the block

D. A sample of gold (Au) has a mass of 26.15 g. Given that the theoretical density is 19.30 g/mL,

We come up with an equation for the total mass of our sealed vial, 2.5X+3.09Y+4.95=30.61 or 2.5X+3.09Y=25.67 when simplified, where X is the number of Pold¬¬¬ , Y is the number of Pnew, and 4.95 is the mass of an empty vial. We also need to make another equation for the number of Pold¬¬¬ and Pnew , X+Y=10.

Determine the weight of the water by subtracting the weight of the vial with water by the weight of the vial on its own.

1.50 "mL methyl-benzoate "×(1.094 "g methyl-benzoate " )/"mL methyl-benzoate " ×(1 "mol methyl-benzoate " )/(136.15 "g methyl-benzoate " )

3. A bullet is fired with a velocity of 200 m/s at an angle of 450 from the horizontal, after approximately 2s, the target is hit. How far is the target placed?

INSTRUCTIONS: Choose the best answer and shade the corresponding circle on your answer sheet. To change your answer, cross-out and sign your original answer and then shade your new answer. No computational devices allowed (e.g. calculators, mobile phones). Following instructions is part of the exam. Useful formulas: Area Sphere (radius = r) Cylinder (radius =r, height = h) 1. Volume Useful constants: e me εo k -1.60 x 10-19 C 9.1 x 10-31 kg 8.854 x 10-12 C2/Nm2 8.988 x 109 Nm2/C2

An ice cube is floating in water above which a layer of a lighter oil is poured. As the ice melts completely, the level of interface and upper of layer of oil surface