This regression equation can be graphed as follows assuming β0 as the intercept and β1 as the slope:
With zeros of a±b. If we say that a = 2 and b = -3, then this function has zeros of 2±(-3). In this form of zeros, we can say that 2 is the x value of the vertex coordinates, lying on the axis of symmetry of Y2 on the x-axis, and ±3 are just the distances between the mid point 2 to the points where Y2 intersects x-axis. It is clearly shown on the graph below.
c. Explain how the location of each curve graphed in question 7b would be altered if (1) total fixed cost had been $100
P B - 2 0 0 6 - 2 | M a y 17, 2 0 0 6
Finally we got all our number and determine the slope, and the intercept in order to find out the forecast for the next
A. -8 + x [(let x be the variable number, therefore sum of variable (x) and (-8) would be x-8 or -8 + x)]
What is its melting point? 1,405 K: 1,132 C: 2,070 F. boiling point? 4,404 K: 4,131 C: 7,468 F
In the following graph, the exponential function has a very similar trend to the trend of y=2x. It is important to note that the exponential function is actually y=ax where a > 0. Using y=1x would only produce a horizontal line. Therefore the next value used was y=2x. In order to make the function fit better with the points we make transformations that slightly change the function. The first step is to lower the line so that the line can become closer to the data points. With this data set it sloa stands to reason that there are negative numbers very much possible. It would work in the exponential equation 2x-1.
Here we have plugged in the values into our formula. When solving we do order of operations first and we will solve exponents first.
First, we need to plug in the variables into the numbers from the information to create our first equation for the system. 3j (glasses of orange juice) + 5p (5 pancakes) = 7.60. Now, plug in the variables into the numbers from the information for the second equation for the system. j ( a glass of orange juice) + 2p ( 2 pancakes) = 2.90.
4) Use cubic regression to determine an equation for the data (or lwh where (12 – x) represents the sides and (x) represents the height of the box).
A(-2, 2) becomes A'(5, 1) , B(-2, 4) becomes B'(5, 3) , C(2, 4) becomes C'(9, 3) , D(2, 2) becomes D'(9, 1)
We made a table to help us figure out how to find the pattern. In Table 1.2, the first column you see the number of cuts. The second column is the most pieces possible, and the last column is the differences we got between the upper bound of the cut before and the cut we were on. For example, we got four pieces for two cuts and seven pieces for three cuts, this means that between two cuts and three cuts there was a difference of three pieces. We noticed that the difference was also equal to the number of cuts.
Knowing this information, you need to first tell me, and then show this in your graph:
The equation of the line in run 1 between the two points is y – y1 = m(x – x1)