Quadratic Functions Essay

2. Describe the pattern of growth in the “Number of people told” column for both Scenario A and Scenario B.

Understand own responsibilities, and responsibilities of others, relting to health and safety in the work setting.

The mean for the column “mean” is 3.56. It is very close to the parameter of interest but is not equal to it. You can calculate a confidence interval for the mean of the mean column, but a specific confidence interval would need to be provided. In that case, the confidence interval would be centered on 3.56, not 3.5.

1.1 - Explain how legislation,frameworks,codes of practice and policies relating to positive behavior support are applied to own working practice?

4) Use cubic regression to determine an equation for the data (or lwh where (12 – x) represents the sides and (x) represents the height of the box).

Briefly explain why the Inverse Floating Rate Bond has a much longer effective duration than the underlying fixed cash flow.

The average number of breakdowns from the simulation trials was 1.93 with a standard deviation of 0.20. No. of breakdowns per week

It is being used in page 22, “Rate, Graph, Slopes, and Equations” Quadratic rate of change comes from the parabola in the graph or the table. We would have to find the rate of change on each point because it won't be constant. y=ax^2+bx+c is the quadratic equation that we can find with the quadratic rate of changes. It’s being used in page 32, “To the Rescue.” Instantaneous rate of change is at a particular instant time at a point of the graph. The derivative is a way to look at by the meaning of instantaneous equal to the instantaneous rate of change. It would help you measure the instant time rather than the time on the table. It’s being used in page 34, “The Instant of Impact.” The derivative approximation is the slope of the line that is tangent to the curve at (a,b). It is also the instantaneous rate at which the y-value of function is changing as the x-value increases through

Solving systems of equations requires prior knowledge of equations. Students must be familiar with how to interchange equations from standard form to slope intercept form. In standard form, which is AX=By=C, the student must recall prior knowledge of how to maneuver the variables in order to isolate the (y) variable one side of the equal sign. Once the student has the equation in slope intercept form , he/she will be able to place the equation in the calculator to graph in order to show which points lie on the (x) and (y)

4. Write a program to calculate and display the result of a second order equation where

This regression equation can be graphed as follows assuming β0 as the intercept and β1 as the slope:

With zeros of a±b. If we say that a = 2 and b = -3, then this function has zeros of 2±(-3). In this form of zeros, we can say that 2 is the x value of the vertex coordinates, lying on the axis of symmetry of Y2 on the x-axis, and ±3 are just the distances between the mid point 2 to the points where Y2 intersects x-axis. It is clearly shown on the graph below.

The line of best-fit is used to find the gradient, the T2/L value, if straight or linear it shows that the relationship between the two is directly proportional. Using the original equation, you can square both sides and rearrange it to make . Then you can input the gradient value (T2/L) and work out g. , where g equals 10.13 m/s2. This value is close to the

The trendline, known as the line of best fit or the least squares regression line, shows the linear equation which best explains the sums up the data’s trend. The formula on the right is the formula of the line of best fit.

The taking 2 points from the graph, (11.8 x 10-3, 2.45), (7 x 10-3, 2.36)