Reaction Of An E1 ( Unimolecular Elimination ) Reaction Essay

In an oxidation reaction, the number of C-H bonds decreases or the number of C-O bonds increases, while in a reduction reaction, the number of C-H bonds increases or the number of C-O bonds decreases. In the oxidation step of this reaction, 4-tert-butylcyclohexanone is formed from when a C-H bond is lost while a C-O bond is gained to create a carbonyl. In the reduction step, 4-tert-butylcyclohexanol is formed when the carbonyl is converted into an alcohol when a nucleophilic hydride attacks the carbonyl. Whether the OH is in the

The carbon-carbon double bond of alkenes represents a site that has a high electron intensity. This site is susceptible to oxidation. Depending on the conditions or reagents used to initiate the oxidation of alkenes, various products can be obtained. With relative mild oxidation, it is only the pi bond of an alkene that is cleaved resulting in the production of 1,2-diols or epoxides. However, when there is more vigorous

We used TLC analysis to identify each product obtained from the dihydroxylation reactions by spotting a TLC plate with the product of our reaction, a solution of cis-cyclohexane, trans-cyclohexane, and a 50:50 mixture of the two. We then placed the plate in a beaker with ethyl acetate saturating the atmosphere to allow the TLC plate to develop. Finally, we compared Rf values of the components of the mobile phase, after the phase was completed. 100% ethyl acetate was used instead of 100% Hexane or a mixture of Ethyl Acetate, because ethyl acetate has high polarity and can separate the components of a mixture to elution, unlike hexane, which is non-polar, and therefore unable to separate the components of the mixture. A 50:50 mixture of both would not work, because the polar and non-polar compounds would neutralize the mixture, and thereby not separate the components of the mixture.

The purpose of this lab was to carry out a dehydration reaction of 2-methylcyclohexanol by heating it in the presence of phosphoric acid and determining which alkene product would be the major product. Methylcyclohexanols were dehydrated in an 85% phosphoric acid mixture to yield the minor and major alkene product by elimination reaction, specifically E1. The alkenes were distilled to separate the major and minor products and gas chromatography was used to analyze the results and accuracy of the experiment. The hypothesis was the major product of the reaction would be the most substituted product. This conclusion was made because of

A unimolecular nucleophilic substitution or SN1 is a two-step reaction that occurs with a first order reaction. The rate-limiting step, which is the first step, forms a carbocation. This would be the slowest step in the mechanism. The addition of the nucleophile speeds up the reaction and stabilizes the carbocation. This reaction is more favorable with tertiary and sometimes secondary alkyl halides under strong basic or acidic conditions with secondary or tertiary alcohols. In this experiment, the t-butyl halide underwent an SN1 reaction. Nucleophiles do not necessarily effect the reaction because the nucleophile is considered zero order, (which makes it a first order reaction.) The ion that should have the strongest effect in an SN1 reaction is the bromide ion. The bromide ion should be stronger because it has a lower electronegativity than chloride as well as a smaller radius.

Based on prior calculations, expected yield for the alkene products was 79.5%. The actual yield was not as high, resulting in a 28.4% yield. Even with this relatively small yield, the reaction still went to completion as indicated by the GC results in Figure 2. This is known because there is no presence of 2-methyl-1-butanol within the GC spectra. Only the two desired alkene products with

The initial product is the beta-hydroxyketone, which rapidly undergoes dehydration and creates the final product, trans-p-anisalacetophenone. Technically, both the carbonyls cannot be mixed together with sodium hydroxide to get one product. We will get a dominant product of trans-p-anisalacetophenone. This reaction is an exception and we get away with it. P-anisaldehyde and acetophenone together only make one enolate. This helps our exception, but there are still two carbonyls. With our weak base, we should be worried about acetophenone reacting with itself but we are not. This is due to steric hindrance, like I stated earlier. Aldehydes are better electrophilic carbons and therefore the ketone will react with the aldehyde faster than reacting with itself. It will quickly form the product trans-p-anisalacetophenone because it is the favored product. We do not have to use expensive LDA, we can use the weaker base and get away with it.

1. Describe the process by which cholera toxin leads to severe fluid and electrolyte loss during diarrhea.

An E1 reaction is a type of elimination reaction in which two substituent groups are removed from a molecule via a two-step mechanism1. One feature of a E1 reaction is the carbocation intermediate. A carbocation is a carbon that has three bonds and a positive charge, but these carbons are very unstable and more reactive because they want to be stabilized. Carbocations can be stabilized with neighboring carbon atoms1.

In this experiment, NaOH was the inhibitor used to stop the enzymatic reactions. NaOH is very basic and when added to a solution, will cause a drastic increase in pH, causing denaturation of the enzyme. The amount of product formed could be calculated by placing the test tube in a spectrometer after the addition on NaOH. A spectrometer measures the absorbance of a solution, which helps compare how much of a substance is in a solution.

The purpose of this lab is to understand the process of eliminating an alkyl halide to form an alkene. The experiment is carried out by first converting the alcohol, 2-methy-2-butanol, into the alkyl halide of 2-chloro-2-methylbutane that will then be put through dehydrohalogenation that favors elimination reaction (E2) to create a mixture of 2-methyl-2-butene and 2-methyl-1-butene. A fractional distillation will be taken to purify the mixture and an additional gas chromatography will be done to further analyze the mixture composition. A bromide test will be done to determine the product of an alkene in the experiment.

This step produces a carbocation. A tertiary carbocation is preferred because it is more stable than a primary or secondary carbocation. The solvent takes a Hydrogen away from the beta carbon and the pair of electrons go to the bond between the alpha and beta carbon creating an alkene, as shown in Figure 1. Essentially, E1 is two steps, the loss of a leaving group and a formation of a carbocation. Figure 1.

This reaction was done at relatively low temperatures as the dry ether has a boiling point of 34.6 °C. At low temperature the endo preference predominates unless there is extreme steric hindrance, which in this case there is not. The endo product forms almost exclusively because of the activation barrier for endo being much lower than for exo. This means that the endo form is formed faster. When reactions proceed via the

As mentioned, this reaction is a type of single replacement reaction, and all single replacement reactions are exothermic, meaning they produce heat. This is because in the reaction:

The oxidation reaction occurs as a two-step reaction. The first step involves the formation of chromate esters and the second step is an elimination reaction that will produce the carbonyl group necessary to make either a ketone or an aldehydes. The reaction is hallmarked by the breaking of a C-H bond and the formation of a C-O bond (James, 2014). Specifically when oxidizing alcohols, it is important to note that primary alcohols can be converted to aldehydes as well as completely to carboxylic acids, secondary alcohols are converted to ketones and no further, and tertiary alcohols cannot be oxidized. The oxidizing agent removes the hydrogen from the –OH group and the hydrogen from the C-H group attached to the –OH group in a compound. Tertiary alcohols cannot be oxidized because they lack the C-H bond that is present in both the oxidation of primary and secondary alcohols (Clark, 2003).