Example Of A Farmer Research Paper

|0 |$ 60 |$ 0 |$ 60 |$ 0 |$ 0 |$ 0 |$ 0 |

P B - 2 0 0 6 - 2 | M a y 17, 2 0 0 6

Solutions: 1a 2c 3c 4d 5d 6c 7c 8d 9d 10a 11d 12a 13c 14c 15d 16c 17c 18b 19b 20c 21d 22a

System.out.println(); System.out.println("Total Sales \t Total Compensation"); System.out.println("----------- \t ------------------"); double minimumSales = 80000; double potentialCommission = minimumSales * 0.05; double potentialCommission1 = 85000 * 0.05; double potentialCommission2 = 90000 * 0.05; double potentialCommission3 = 95000 * 0.05; double potentialCommission4 = 100000 * 0.0625; double potentialCommission5 = 105000 * 0.0625; double potentialCommission6 = 110000 * 0.0625; double potentialCommission7 = 115000 * 0.0625; double potentialCommission8 = 120000 * 0.0625; double potentialCompensation = salary + potentialCommission; double potentialCompensation1 = salary + potentialCommission1; double potentialCompensation2 = salary + potentialCommission2; double potentialCompensation3 = salary + potentialCommission3; double potentialCompensation4 = salary + potentialCommission4; double potentialCompensation5 = salary + potentialCommission5; double potentialCompensation6 = salary + potentialCommission6; double potentialCompensation7 = salary + potentialCommission7; double potentialCompensation8 = salary + potentialCommission8;

rr  rtsj  idj  rr  rts−1. Since y is from the previous round, rts would be equal to rts−1

0 1 1 0 0 0 0 1 64+32+1=97, This is the ASCII code for A

23 Subtract line 22 from line 15 . . . . . . . . .

0 14 408 0.193 1,284 0.61 168 255 418 261 142 1.7d 0.8d 60.2f 10.0f 0.22f 64.9f 1,671f 573 52.5 18,400i 79,700 482 14 24 7 19 15 742 552 11,772 14

5.000,00 $ 7.500 151.250 20 35.000,00 $ 12.500 321.250 26 $ 58,20 $ 110.000,00 4.000 333.500 83 115,38

The Wiethoff Company has a contract to produce 10000 garden hoses for a customer. Wiethoff has 4 different machines that can produce this kind of hose. Because these machines are from different manufacturers and use differing technologies, their specifications are not the same.

1,300 1,200 1,100 1,000 900 800 700 600 500 400 300 200 100 0 0 5,000 10,000 15,000 20,000 25,000

2(X4 + X5 + X6 + X7 + X10 + X11 + X16 + X17 + X18 + X27 + X28) – (X1 + X2 +X3

14 x C-H (412) + 4 x C-C (348) + 2 x C-O (360) + 2 x O-H (463) + 9 x O=O (498)  12 x C=O (805) + 16 x O=H (463)

∏i = (Pe + 40 - 100) x 100 = 100 x Pe –6,000 -------------------- [1]

PART A – Linear Programming 1 a) Linear Programing Model Decision Variables: Let x = acres of watermelon Let y = acres of cantaloupe Objective Function: Maximize Z = 390x + 1300y – 5(20x + 15y) + 5(2x + 2.5y) = 270x + 300y – 100x + 75y + 10x + 12.5y = 256x + 284.5y where Z = total profit 390x = profit from watermelons 1300y = profit from cantaloupe 5(20x + 15y) = cost of fertilizer 5(2x + 2.5y) = cost of labour Identification of Constants: Maximize Z = 256x + 284.5y