Honours Chemistry 11
Sleuth Your Slurry
This labaratory report shows that when presented with an unknown chemical substance, identification of that substance is revealed through a seires of tests that involve chemical and physical properties of that substance.
You are given an unknown chemical substance that you need to be able to identify. How are you going to do this? The compound can be either harmful or toxic, so what you need to do is test all of its physical and chemical properties, and then find out the synthesis of the substance. Qualitative testing and quantitative testing is essential in discovering what the unknown is.…show more content… 6. Since I mixed my unknown with and it formed a percipitate, I am able to conclude it is insoluble. I compared the results with other anions from my table of solubilities, and phosphate’s results are the only ones that matched with mine, but sulfate’s did not. This helped me to figure out the known anion.
Cation Percipitate Test #3
1. For this percipiate test with my unknown H chemical, I mixed it with , or Copper III nitrate. The purpose of this test was to determine whether my unknown formed a percipitate with this compound, and to eliminate cations.
2. If the reaction with is insoluble, it would allow me to eliminate suspected cations to get closer to the real cation. Since my cation for my unknown is soluble in most reactions, I attempted to mix it with Copper (II) nitrate, and compare them with the results of phosphate mixing with Copper (II) nitrate.
3. This test requires a spot plate cleaned with distilled water. Then, after adding 2 drops of to one section of the plate, add 2 drops of unknown H. Record results, and then compare with result of phosphate and . This double replacement reaction will yield and . It is possible to separate the two chemicals because nitrate is soluble and Copper is not.
4. C= cation A=anion
+ CA CuA (ppt) + C + (s) this reaction produced partially soluble percipitate with blue specks floating around.
5. By looking at my table of solubilities, it is possible to eliminate most cations because