# Statistic Analysis: A Questionnaire

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Statistic Analysis (12 points) In this recession, yours truly would like to make extra money to support his frequent filet-mignon-et-double-lobster-tail dinner habit. A promising enterprise is to mass-produce garnet wedding rings for brides. Based on my diligent research, I have found out that women's ring size normally distributed with a mean of 6.0, and a standard deviation of 1.0. I am going to order 5000 garnet wedding rings from my reliable Siberian source. They will manufacture ring size from 4.0, 4.5, 5.0, 5.5, 6.0, 6.5, 7.0, 7.5, 8.0, 8.5, 9.0, and 9.5. How many wedding rings should I order for each of the ring size if I order 5000 rings altogether? (Note: It is natural to assume that if your ring size falls between two of the above standard manufacturing size, you will take the bigger of the two.) Mean =total sum of size/total number =6 Sum of 12 sizes = (4.0+4.5+5.0+5.5+6.0+6.5+7.0+7.5+8.0+8.5+9.0+9.5) =81 Mean size=81/12 =6.75 Sum derived from mean=6*12=72 Let m be number out of 12 numbers 5000*6=6.75*m Hence m=4444.444 Therefore the amount you should order is =4444.44/12 =370.37 (8 points) According to a study by my PseudoScientific Consulting, the time interval between Atlantic hurricane of category 4 has a mean of 456 days and a standard deviation of 123 days. Suppose that you observe a sample of five (5) time intervals between successive category 4 hurricanes On average, what would you expect to be the mean of the five (5) time intervals?