Statistics Questions

391 WordsJan 9, 20182 Pages
January 13 2) ETA = 1 V1 10 m/s V2 0 m/s V11 0 m/s V21 10 m/s H1 100 kg (m/s) H2 0 kg (m/s) Total H =H1 +H2 = 100 kg (m/s) H11 0 kg (m/s) H21 100 kg (m/s) Total H1 =H11 +H21 = 100 kg (m/s) KE1 500 J KE2 0 J Total KE = KE1+KE2 = 500 J KE11 0 J KE21 500 J Total KE = KE11+KE21 = 500 J Momentum and energy are conserved as the numbers are equal before and after the collision. 3) ETA = .7 V1 10 m/s V2 0 m/s V11 1.5 m/s V21 8.5 m/s H1 100 kg (m/s) H2 0 kg (m/s) Total H =H1 +H2 = 100 kg (m/s) H11 15 kg (m/s) H21 85 kg (m/s) Total H1 =H11 +H21 = 100 kg (m/s) KE1 500 J KE2 0 J Total KE = KE1+KE2 = 500 J KE11 11.25 J KE21 361.25 J Total KE = KE11+KE21 = 362.5 J Momentum is conserved but not energy following the collision. 4) ETA = .3 V1 10 m/s V2 0 m/s V11 3.5 m/s V21 6.5 m/s H1 100 kg (m/s) H2 0 kg (m/s) Total H =H1 +H2 = 100 kg (m/s) H11 35 kg (m/s) H21 65 kg (m/s) Total H1 =H11 +H21 = 100 kg (m/s) KE1 500 J KE2 0 J Total KE = KE1+KE2 = 500 J KE11 61.25 J KE21 211.25 J Total KE = KE11+KE21=272.25 J Momentum is conserved but not energy following the collision. 5) ETA = 0 V1 10 m/s V2 0 m/s V11 5 m/s V21 5 m/s H1 100 kg (m/s) H2 0 kg (m/s) Total H =H1 +H2 = 100 kg (m/s) H11 50 kg (m/s) H21 50 kg (m/s) Total H1 =H11 +H21 = 100 kg (m/s) KE1 500 J KE2 0 J Total KE = KE1+KE2 = 500 J KE11 125 J KE21 125 J Total KE = KE11+KE21=250 J 6) A low coefficient of restitution constitutes high energy loss, while a high coefficient of
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