Statistics Worksheet

c) The average, or mean of the measurements are almost the same in both cases. However, the standard deviation of the CEOs’ measurements is almost double of the governors’, which means that the CEO’s desks can be either much bigger or much smaller than the governors.

2) Compute the standard deviation for each of the four samples. Does the assumption of .21 for the population standard deviation appear reasonable?

The mean for the median column is 3.6, which is close to the mean in question 2 but not as close as the answer in question 3.

1. By hand, compute the mean, median, and mode for the following set of 40 reading scores:

First we find E by doing Zc(standard deviation/square root of number of trials.) Now we add and subtract that number from the mean income to find both endpoints. The Zc of 95% is 1.96 so we would do

Standard Deviation for the mean column is 0.476Standard Deviation for the median column is 0.754Standard deviation for the mean column has least variability

σA = 0.3 × (0.07)2 + 0.4 × (0.06)2 + 0.3 × (0.08)2 − (0.021)2 = 0.004389,

2. For the following set of scores, fill in the cells. The mean is 74.13 and the standard deviation is 9.98.

The t-test is a parametric analysis technique used to determine significant differences between the scores obtained from two groups. The t-test uses the standard deviation to estimate the standard error of the sampling distribution and examines the differences between the means of the two groups. Since the t-test is considered fairly easy to calculate, researchers often use it in determining differences between two groups. When interpreting the results of t-tests, the larger the calculated t ratio, in absolute value, the greater the difference between the two groups. The significance of a t ratio can be determined by comparison with the critical values in a

Fry Brothers heating and Air Conditioning, Inc. employs Larry Clark and George Murnen to make service calls to repair furnaces and air conditioning units in homes. Tom Fry, the owner, would like to know whether there is a difference in the mean number of service calls they make per day. Assume the population standard deviation for Larry Clark is 1.05 calls per day and 1.23 calls per day for George Murnen. A random sample of 40 days last year showed that Larry Clark made an average of

Of the three independent variables, the first variable is law enforcement. The law enforcement variable has a minimum range of $0.00 and a maximum range of $83,057.14. Its mean average is 907.27 and its standard deviation is 6298.88. The second independent variable is the fire control variable and it has a minimum range of $0.00 and a maximum range of $2,198.85. Its mean average is equal to 112.56 and its standard deviation is equal to 195.65. The final independent variable is the parks and recreation variable and it has minimum range of $0.00 and a maximum range is $1,054.45. Its mean average is equal to 86.38 and its standard deviation is equal to 119.98.

I have placed the results from our experiment in form of a table and will use the average results to form a graph. I have also prepared a graph to show the results throughout the exercise.

The standard deviations Sx and Sy have been found using the following table of data:

Enter these results into your graphics calculator and determine the 5 figure summary for Steve’s 42 best test scores and the mean.

It shows that the Mature Group has a higher mean score with 22.4 and the Young Group has a lower score with 21.4, with a difference of 1 between both scores.