Statistics and Mean Selling Price

So, we should reject the null hypothesis H0. At a 0.05 level of significance level, we conclude that there is a significant difference between the average height for females and the average height for the males.

3. Write the answer to the following problems in the correct number of significant figures.

(e) Is there a significant relationship between the selling price and the assessed value of the house? Use 5 % level of significance.

|A random group of apartments was selected from a city to analyze the number of bedrooms they have. Is there evidence to reject |

Do Number of Stores Influence Conclusion- This has no impact on conclusion because the data range for stores was from 27 to 87 giving it a mean of 59.8 and SD of 27.5. This demonstrated that the numbers of stores that participated in the programs was sufficient enough to analyze and interpret. Program V just happens to have the highest number of stores participating, but that would be irrelevant if it wasn’t the most profitable.

(21) You took a sample of size 21 from a normal distribution with a known standard deviation, . In order to find a 90% confidence interval for the mean, You need to find.

6. Based on questions 3, 4, and 5 is the mean or median a better estimate for the parameter of interest? Explain your reasoning.

First we find E by doing Zc(standard deviation/square root of number of trials.) Now we add and subtract that number from the mean income to find both endpoints. The Zc of 95% is 1.96 so we would do

estimates that a bid of $5 million will have a 0.2 probability of being the highest bid and

“Hypothesis testing is a decision-making process for evaluating claims about a population” (Bluman, 2013, p. 398). This process is used to determine if you will accept or reject the hypothesis. The claim is that the bottles contain less than 16 ounces. The null hypothesis is the soda bottles contain 16 ounces. The alternative hypothesis is the bottles contain less than 16 ounces. The significance level will be 0.05. The test method to be used is a t-score. The test statistic is calculated to be -11.24666539 and the P-value is 1.0.  The P-value is the probability of observing a sample statistic as extreme as the test statistic, assuming the null hypothesis is true. The T Crit value is 1.69912702. The calculations show there is enough evidence to support the claim that the soda bottles do

At the .01 significance level is there a difference in the mean amount purchased on an impulse at the two stores? Explain these results to a person who knows about the t test for a single sample but is unfamiliar with the t test for independent means.

Conclusion : Reject the null hypothesis. The sample provide enough evidence to support the claim that mean is significantly different from 12 .

How many repair records should be sampled if the research firm wants the population mean number of miles driven until transmission failure to be estimated with the margin of error of 5000 miles? Use 95% confidence.

To verify the claim that the bottles contain less than sixteen ounces of soda a hypothesis test will be performed. To find the null hypothesis that represents the claim to be true or to be used as a basis of argument until it is proven. The null hypothesis is H0 greater than or equal to sixteen ounces. The alternative hypothesis is H1 less than sixteen ounces. The type of test used is one tailed testing. If using a significance level of .05, a one-tailed test allots the entire alpha to testing the statistical significance in the one direction of interest.  This means that .05 is in one tail of the distribution test statistic. When using a one-tailed test, it is testing for the possibility of the relationship in one direction and completely disregarding the possibility of a relationship in the other direction ("UCLA: Statistical Consulting Group," 2007). The value of the test is calculated by the mean 1 minus mean 2. Therefore, 14.87 – 16 equals -1.13 divided by standard deviation 0.55 divided by square root of random sample 30 equals .375. The P value is calculated by using the formula P (Z < equal to .375). The P value is 0.646. The P value is greater than the significance level of test which is .05. The answer is the mean of 0.5 < 0.646. The conclusion of the test for the null hypothesis is not rejected. This suggests the alternative hypothesis must be true that the soda in the bottles is less than sixteen ounces. The type of error

5) From calculations, computed z value is more than -1.65 and falls within Ho not rejected region. Ho is not rejected at α = 0.05 &amp; α = 0.01 significance levels.