Survey on Teenagers Pocket Money

5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?

A business wants to estimate the true mean annual income of its customers.  It randomly samples 220 of its customers.  The mean annual income was $61,400 with a standard deviation of $2,200.  Find a 95% confidence interval for the true mean annual income of the business’ customers.

5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?

The most appropriate measure for this data set would be mean as it involves all the numbers combined.

Based on the given sample of student test scores of 50, 60, 74, 83, 83, 90, 90, 92, and 95 after rearranging them from least to greatest. As the mean is based on the average of sum, the average of this sample is 79.67 or 80. The mode refers to numbers that appear the most in a sequence and in this case 83 and 90 both appear twice. Range calculates the difference between the largest and smallest number, which are 95 and 50 which have a difference of 45. The variance is the difference between the sum of squares divided by the sample size, which is the number in the sample minus one (Hansen & Myers, 2012), meaning it takes each number of the set and subtracts

Median: 3, 5, 11, 12, 13, 15, 19, 35, 42, 65 = 13 + 15 = 28/2 = 14

The median is basically the middle score for a set of data that has been arranged in order of extent. The median is less affected by outliers and twisted data

For the education data, I must say to calculate the median, from high school to college graduate, the median would be the some college portion since it would be the middle. The median for the experimental group would be 11 and 34.4% and for the control group it would be 15 and 41.7%.

The student height for boys has bimodal data because there are 2 peaks in the data. The 2 peaks are the average height of class QT-9 and the mean height of QT-1.

9. Assume you want to estimate with the proportion of students who commute less than 5 miles to work within 2%, what sample size would you need?

I believe that in the verge of realization, in everyday life’s undertaking we are facing and practicing statistics. I was being into a serious dedication of understanding the underlined concepts of statistics and the necessary usefulness in conducting a survey. In fact, throughout the course, I did learn many factors that became useful in contacting a survey research. according to Walker et al. (2011). However, my success could not be possible without the appreciation and support of my teachers, discussion groups, and class presentations.in addition, the misguided notion of statistics being a tough course was proven otherwise since I realized that statistics make a lot of sense not only in survey research in personal life, especially in budgeting and planning for individual routines. Furthermore, the following paper provides a vivid explanation of my reflection of the survey class, with more attention paid to the concepts of statistics.

The example below lists the results for numbers 6-10. The measures of central tendency include mean, median, and mode. In this example the measures of central tendency will be calculated based on row B, which indicates the number of months that a particular employee has been with the company. The data being analyzed is the

Included in this report is an excel file with all the scores used to calculate the following data, it will help understand the following central tendency better, as far as where these numbers were taken. Central tendency includes the commonly used mean, mode and median. This helps analyze data more effectively and for through understanding of research. I will highlight the most significant ones here.

Based on the chart, the mean was calculated by adding up the sum of the list and divide 18, which the number of the total listed prices. The mean is 135,000, which mean the average of the listed price. Secondly, the median was calculated by listing the number in numerical order from lowest to highest and located the number in the middle 126,000. The median represents the middle number of the listed price. After calculating the median I located the minimum and maximum based the lowest and highest data, which are 48,000 and 338,000. These represent the range of the listed price. Lastly, I used the formula to get the

Determining the mean and the median of the checking accounts for Century National Bank, we are trying to find the single value that will represent all 60 checking accounts in our sample. That single value will be measure of central tendency.