The purpose of this assessment is to demonstrate in a clear, precise way, how to answer identified NAPLAN (National Assessment Program – Literacy and Numeracy) questions. NAPLAN is a standardised test developed by Australian Curriculum, Assessment and Reporting Authority [ACARA] (n.d.). This assessment will provide answers to each question and will indicate the confidence with the approach used, how each answer was formulated, the steps taken or knowledge used and whether that knowledge was known or investigated. This assessment will also show what other way could have been used to answer each question. Precise mathematical procedures will be used to solve these equations, moreover as much detail as possible will be provided to produce …show more content…
Observing problems in concrete form aids in my understanding and therefore the solution. Conversely, the drawing of the diagram in a two-dimensional form helped to deliver the correct answer. I approached this question with the required knowledge and confidence to solve it immediately.
Question 5, NAPLAN (Year 9 non-calculator), ACARA (2012)
Approach: The approach used to solve this scale was ratio set up in the form of a fraction.
Workings: To calculate the ratio, the actual length measurement is divided by the drawing length measurement. The measurements need to be represented in fraction form. The drawing length is 4cm and the actual length is 8mm.
Actual length over the drawing length: 8mm/4cm.
Simplify this fraction by determining the largest common denominator of both numbers. The largest common denominator of both numbers is 4.
8mm/4cm : 2mm/1cm . Drawing length becomes 1cm and actual length becomes 2mm. The scale is 1cm represents 2mm.
Another way to solve this question would be by using data measurement with the mathematical concept of division, using part/whole method. Both shapes were square and would be able to be divided equally. Using the part/whole method and establishing the number four was one of the common denominators for both lengths.
DL = 4cm. 4cm ÷ 4 = 1cm : AL = 8mm. 8mm ÷ 4 = 2mm
Scale of drawing = 1cm represents 2mm
I was confident
All i did for this one was basically calculate the slopes because I didn't want to over think the question. Based off the figures let's calculate the following slopes...
To convert it to cm, you must times it by 1,000,000, so it is now 198,134,664cm3.
3. The distance between scale markings on the horizontal scale is 100 km. Comparison of the vertical and horizontal scales indicates that the vertical scale is exaggerated [(10)(100)(1000)] times relative to the horizontal scale.
a. Given that one inch = 2.54 cm. State the student's height in inches and then convert to centimeters. (4 points)
6. If an object is 4.5 cm long, what would its length be in mm?
heavy duty samples as well as your dimensional measurements (length and width in cm) from Part III of this experiment, calculate the height, or thickness, of each sample of aluminum using the formula V l x w x h. In the formula, V stands for volume, l for length, w for width, and h for height. Once again, you will have to use your algebraic skills to manipulate the formula, to solve for height. You must show all your work. (15 pts)
What is a ratio? What are the different ways of expressing the relationship of two amounts? What information does a ratio provide?
At first I did not not feel very confident when trying to answer this question because I could not remember the method involved when converting scale. I was able to interpret the question and I understood what it required; however, I could not recall the process involved in reaching the answer. After trying a few different methods and giving it some thought, I remembered what to do. I had learnt how to answer these questions in high school geography and I still had the knowledge, but I just had to go through the process of recalling it. So, the method I used to solve the problem was to write out the scale used in the diagram as a ratio, simplify it and then convert it to a written statement. Thus, I was unsure about how to answer this question
Think about what you need to measure before you measure. i.e., I want to measure to see how long Charles’ body is
41. On a map with a scale of 1:50,000, the distance between point A and B is 18 centimeters. What is the actual ground distance in meters?
Assessment is carried out through formative (checks throughout the course), ipsative (to test against previous marks), and/ or summative (at end of course) activities to help the learner see their development whilst allowing the Assessor to give valuable feedback when appropriate. It’s purpose is to measure the learners understanding of the subject against the anticipated outcomes set by the criteria.
Knowing this information, you need to first tell me, and then show this in your graph:
teacher I am required to take into account both dimensions. So this became my goal and tool to use.
Find the average distance of Pluto from the Sun. Using the same scale as Procedure B, calculate the scaled distance that Pluto should be on your model. Show your work! 5,906,376,200 / 25,000,000 = 236.25cm ~ 236 cm
Distinguishing between scale and proportion is significant in depicting a specific image in which the size is questionable and cannot be visualized accurately. According to the textbook, scale is the size relation of one thing to another. However, Proportion is