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The purpose of this assessment is to demonstrate in a clear, precise way, how to answer identified NAPLAN (National Assessment Program – Literacy and Numeracy) questions. NAPLAN is a standardised test developed by Australian Curriculum, Assessment and Reporting Authority [ACARA] (n.d.). This assessment will provide answers to each question and will indicate the confidence with the approach used, how each answer was formulated, the steps taken or knowledge used and whether that knowledge was known or investigated. This assessment will also show what other way could have been used to answer each question. Precise mathematical procedures will be used to solve these equations, moreover as much detail as possible will be provided to produce
*…show more content…*

Observing problems in concrete form aids in my understanding and therefore the solution. Conversely, the drawing of the diagram in a two-dimensional form helped to deliver the correct answer. I approached this question with the required knowledge and confidence to solve it immediately.

Question 5, NAPLAN (Year 9 non-calculator), ACARA (2012)

Approach: The approach used to solve this scale was ratio set up in the form of a fraction.

Workings: To calculate the ratio, the actual length measurement is divided by the drawing length measurement. The measurements need to be represented in fraction form. The drawing length is 4cm and the actual length is 8mm.

Actual length over the drawing length: 8mm/4cm.

Simplify this fraction by determining the largest common denominator of both numbers. The largest common denominator of both numbers is 4.

8mm/4cm : 2mm/1cm . Drawing length becomes 1cm and actual length becomes 2mm. The scale is 1cm represents 2mm.

Another way to solve this question would be by using data measurement with the mathematical concept of division, using part/whole method. Both shapes were square and would be able to be divided equally. Using the part/whole method and establishing the number four was one of the common denominators for both lengths.

DL = 4cm. 4cm ÷ 4 = 1cm : AL = 8mm. 8mm ÷ 4 = 2mm

Scale of drawing = 1cm represents 2mm

I was confident

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