Many things can’t be explained, but I have explained a few things that might seem confusing. If distance equals rate times time, than how fast the object is going, and how long the object is staying in the air is key. The machine that works faster and keeps the object in the air longer should be better than the other. Unless there is a difference in the objects, as such as one might be lighter, or float to stay in the air longer. Or if one object is more aerodynamic than the other. The area in the scoop is much larger than the claw. Therefore it would be slower, and requiring more energy to move and to toss the object. But more force per area would be applied on the object, which could make it go farther. There are endless possibilities to…show more content… The lever propelling the claw tossing the object uses the law of torque and the law of energy. The gear motors moving the claw use the fulcrum of the lever holding the claw. Therefore launching the object and sending it through the air to its supposed target. The torque and energy used is supplied by the gear motor moving the lever and claw (Physics Forums).
The scoop on the end of the lever provides same as the claw, but extra force. Though you would also need more torque and energy to move the scoop tossing the object to its said target. The lever would need to change to a different spot on its fulcrum for maximum reach and to increase the distance for the object to go. There would be very little or no change to how far the object might go compared to the claw (Physics Forums). I believe that the scoop will toss the object farther, just based on the fast that it is bigger and needs more power than the claw. I will test the claw with a small object to toss, and watch how far and high the object goes in the air. I will do the same with the scoop and compare the differences, if any at all. That is all that is needed to explain my