Determination of a Rate Law Megan Gilleland 10.11.2012 Dr. Charles J. Horn Abstract: This two part experiment is designed to determine the rate law of the following reaction, 2I-(aq) + H2O2(aq) +
¬¬¬¬¬¬04/28/2010 Monday & Wednesday 7:40-10:30 Experiment #2 – Kinetics of the Decomposition of Hydrogen Peroxide Introduction: Chemical reactions are dependent upon two factors: temperature and concentrations of substance. We can monitor the rate at which a chemical decomposes or the rate at which a chemical substance appears. In this experiment we will be measuring the rate of decomposition of hydrogen dioxide with the following reaction:
Trial one went with my data successfully, with five different temperatures of hydrogen peroxide. The starting temperature was near freezing point at one degree Celsius, then to eleven, twenty, thirty, and ending at forty.
The percent mass of each component of the mixture was 23% iron, 61% sand, and 8.7% salt.
Question 1. The boiling point elevation constant for water that was experimentally determined in this analysis was 0.4396 °C/m, which was derived from the slope of the trend line in Figure 2. This is slightly lower than the constant provided in lecture of 0.51 °C/m. This could be due to further evaporation of water from the solutions tested via refractive index after the boiling temperature was recorded.
If there is an additional unmeasured amount of water in the Erlenmeyer flask, then this would reduce the concentration of the HCl, and therefore reduce the molarity. The volume of the amount of HCl solution added would increase, yet the concentration of the HCl would remain the same, which would ultimately result in the molarity of the HCl being lower than in reality.
In this experiment, a mixture of unknown #3 was used. That mixture had acid, base, and neutral. We added solvent to the unknown. It is important to know the density of the solvent in order to determine which is the aqueous layer and which is the organic layer. If the solvent that has more density than water, so the organic layer will be the lower layer, while if the solvent has lower density than water, the organic layer will be the upper layer. This will make an error if the determination of the layers was wrong after added the strong acid or the strong base. We added 5% HCl to the mixture in order to separate the base in the aqueous layer and form its salt. Same thing, we add 5% NaOH to the mixture in order to separate the acid and form its salt. In order to recover the base, we add 10% NaOH to the HCl extraction. The result will be salt with a base. Same thing for the acid, in order to recovered it, we added 10% HCl. The reaction will give us salt with an acid. For the neutral, we added sodium sulfate as a drying reagent in order to dry water and separate the neutral part as pure.
1. In the human blood, there is the bicarbonate buffer system. CO2 is released from cellular respiration and then taken up by red blood cells. Next, it is changed to carbonic acid which dissociates to form bicarbonate and H+ ions. 2. In Part I of this experiment, acetic acid is titrated
The main purpose of the lab “Determination of the Formula of a Copper Oxide” was to determine the formula of a copper oxide. Specifically, this is a compound of copper combined with oxygen. This was to be done by heating the copper oxide thoroughly until all of the oxygen had been driven off. To accomplish this experiment, we first had to take and measure the mass of a specified color of copper oxide, ours being red. Then, we used a fischer burner to provide the heat needed for the split of copper oxide, in which our amount resided in a test tube. But, in order for the copper to not recombine with oxygen that could be found in the surrounding atmosphere of our lab, we also had to have a flow of methane gas into the test tube that fed into
Processing : The initial magnesium had a mass of 0.06 g while the final compound had a mass of 0.08 g. Magnesium oxide had been formed, and no magnesium should have been lost over the process due to magnesium being unable to form gases or liquids with any of the elements it had been exposed to.
Introduction: Chemical reactions make new things by rearranging other things. In a chemical reaction, the main change that occurs relates to the way atoms are bonded to each other, in order to change those connections, bonds must be broken and new bonds be formed.
Thermodynamics Laboratory Report Greenwich University By Mussie Gebre 26/01/2011 Content Page Objectives-------------------------------------page3 Introduction----------------------------------page3 Operation (process) ------------------------page3 Result and discussion-----------------------page4 Experimental data and plot-------------page4&5 Conclusion -------------------------------------page6 Mussie Gebre ID 000517715 Thermodynamics laboratory report Objective * Experiment on four different metals on their heat conductivity * To understand thermodynamics * To illustrate the physical concept of thermodynamics and heat However it shows some difference on the actual value of the measurement l = lo (1 + T) Copper: l= 88(1+16.6x10-6x30.3) = 88.044mm lo=88mm | y=16.6x10-6 | ∆T=30.3◦C | l=? | Aluminium lo=79mm | y=25 x 10-6/ºC | ∆T=36 ºC | l=? | l = lo (1 + ∆ T) l=79(1+25 x 10-6/ºC x 36 ºC =79.07mm Brass lo=88mm | y=18.7 x 10-6/ºC | ∆T=47.9 ºC | l=? | l = lo (1 + ∆ T) l=88(1+18.7 x 10-6/ºC x47.9 ºC) =88.07mm Iron lo=88mm | y= 12x 10-6/ºC | ∆T=? | l=88.1 | ∆T=lloy)-1 = 88.1∕88x12x 10-6/ºC -1 Conclusion Overall, the experiment succeeded that the metals show the theoretical properties. Differences existed in the mathematical calculation of the actual length. These differences, however, it can be accounted for by experimental error; more over there are uncertainty on purity of the
Abstract This lab is performed in order to determine the total energy in a reaction between zinc and hydrochloric acid. The reaction is done twice, once to measure the heat of the reaction and again to determine the work done in the system. This is because Enthalpy equals heat plus work (∆H= ∆E+W). Heat and work can be broken down further into separate components so the equation used in lab is ∆H=mc∆T + PV. Many calculations are used in the lab to find out what cannot be measured directly (ex: volume). After all the calculations were complete it was shown to have a very small percent error.
Lab Report: Heat of Neutralization Abstract This experiment was performed to determine the heat of neutralization between Hydrogen chloride (HCl) and Sodium hydroxide (NaOH). A temperature probe was used to measure the temperature of the reaction when the base (NaOH) was poured into the acid (HCl). The data was collected on logged on LoggerPro.
Purpose Question and Background Information: What are the effects of different temperatures on the decomposition of Hydrogen Peroxide with the Enzyme Catalase. Different enzymes work best at different optimal temperatures, and with this experiment we hope to discover which temperatures are unideal for Catalase. The substrate is H2O2 which binds to the active site of the enzyme Catalase. The reaction in question is as written below: