Upl Locus Case Study

2. Indicate on your pedigree chart the individuals who are carriers by shading half of each circle or square.

• Use these data to construct a map of these three genes in two steps.

When you record phenotypic ratios for a monohybrid cross, there are only two possible phenotypes - either the dominant phenotype or the recessive phenotype. So you do not need to indicate the phenotype, simply put the dominant # first, followed by the recessive #:

A 3. G 4. J 5. D 6. B 7.

1. (2 marks) In this experiment, you have amplified the D1S80 locus by PCR. Explain the advantages of using this locus to distinguish one person from another. Do you think you could use a coding gene for the same purpose? Clearly explain your answers.

(e) The largest DNA fragment on the gel belongs to the mother of Couple B and

The two bands are due chromosome pairing, one contains a retrovirus in that section, the other does not (heterozygous).

Now you have determined some facts about the grounded allele and the trait that it causes. Given what you know, do you expect the mutant F1 flies to be homozygous or heterozygous for the allele that causes the grounded trait? According to your reasoning, if you mated two mutant F1 flies, what percentage of flies would you expect to be wild type versus mutant in the F2 progeny? Draw a Punnett square of this cross to justify your answer.

Highlight the base, take a screen shot of the waveform, and paste in a screen shot of this region of the DNA sequence waveform highlighting the start base here:

the definition of sex-linked genes, and examples of sex-linked genes in humans and other organisms

The objective of the project is to be able to determine which alleles are carried at the TAS2R38 locus and verify if the genotype reflects the expected phenotype.

In the allele family IIa, three subtypes were seen; one subtype had 15 copies of the TCA repeat and 1 copy of the TCG repeat, whereas the other subtype had 20 copies of the TCA repeat and 3 copies of the TCG repeat also, another subtype had 16 copies of the TCA repeat and 2 copy of the TCG repeat by two famili. Therefore, the three subtypes were designated respectively IIaA15G1R1, IIaA20G3R1 and IIaA16G2R1.

The ancestral allele is Adenine (A), the alleles may either be adenine or Guanine (G). It must always be remembered that alleles are in pairs due to the formation of genetic material from two different haploid sources: paternal and maternal - and the pair of chromatids forming the chromosome. Therefore, the resulting combinations of alleles can be homozygous (two identical alleles i.e. AA or GG) or heterozygous (two different alleles i.e.

corn was counted off of the ears of the corn, rather than through jars. For the

The pairs of alternative traits examined segregated among the progeny of a particular cross, some individuals exhibiting one traits, some the other