# include <iostream>
# include <list>
# include <map> using namespace std;
//--------------------------------------------------------------------
//Constants assigned to max, min draw const int MAX = 1; const int MIN = -1; const int DRAWE = 0; const int MAXIMUM_SQRS = 9;
//-------------------------------------------------------------------
// Alpha Beta Pruning turned on bool alpha_beta_on = false;
//compare the results of using alpha beta pruning and minimax static int counter = 0;
//assign each column, row and diagnal values inline bool LC(short x)
{
return (x & 0x49) == 0x49;
}
inline bool MCL(short x)
{
return (x & 0x92) == 0x92;
}
inline bool RC(short x)
{
return (x & 0x124) == 0x124;
}
inline bool TR(short x)
{
return (x & 7) == 7;
}
inline bool MR(short x)
{
return (x & 0x38) == 0x38;
}
inline bool BR(short x)
{
return (x & 0x1C0) == 0x1C0;
}
inline bool D1(short x)
{
return (x & 0x111) == 0x111;
}
inline bool D2(short x)
{
return (x & 0x54) == 0x54;
}
typedef int utility;
//--------------------------------------------------------------------------
//initiate action to achieve a new game state class action { public: action() { a_ = 0; side_ = 0; } action(short a, short side) { a_ = a; side_ = side; } enum { MIN = 1, MAX = 2 }; short a_; short side_;
};
//----------------------------------------------------------------------------
//game state that assigned to each x
Minimum element was initially zero, which resulted in a wrong output. Using the debugger to check how For-Loop iterated, I found the initial problem of min = 0 that caused IF statement to be always False. Thus, I changed min=0; to min=num[0] and the program begun to work perfect.
We are using two FOR Loop to traverse the input and create a 2 dimensional array for printing the output.
Provide formulas in cells M2 through M8 that square the differences found in cells L2
2 8 ,8 0 0 -b p s m od em a n d 1 0 b its p er ch a ra cter. Now ca lcu la te th e file tra n s fer tim e for
For this assignment I develop and either pseudo code or a flowchart for my following programming problem.
TP2 is the output of an XNOR gate. The Boolean operator for the XNOR gate is , the XNOR gate requires an inversion bar over the entire expression, and the inputs are C and. Refer to Chapter 3 of the textbook for more information.
Problem Set 2 is to be completed by 11:59 p.m. (ET) on Monday of Module/Week 4.
In this assignment, I will be explaining very briefly some few concepts in order for you or someone else to understand the steps, the graphics and the written methodologies that I will be engaging in order to tackle this Programming Assignment task. In addition, I will be demonstrating how I arrived as my Choice and Solution.
A should bitwise XOR αS and βS (The result of this step is Main Key (MK) for USEA)
if (x > 1) AND (cSpinValue <> 0) AND (cSpinValue MOD 2 = 0) AND (previousSpinValue MOD 2 = 0) then
F e b r u a r y 1 0 , 2 0 0 6
: Whenever the if-statements are used they should be written in a well formatted order. In the case of deep nesting of if-statements there are higher chances of not understanding of the code. The reason for this might be the statements are not
(b) How might you determine whether the pre-recorded music compact discs and MP3 music players are in competition with each other?
This procedure is repeated for each column j = 1; : : : ; n, to obtain h. Then the same algorithm
R = [█(-1-1-1@-1 1-1@-1 1 -1@1-1-1@-1-1-1@-1 1 0@1-1-1@1-1-1@1 1 1@-1-1-1@-1 1-1@-1-1 1@1 -1-1@0 0 0@-1 1 1@1-1-1@1 1 1@1 1 1@-1-1-1@-1 1-1@-1 1 1@1 -1 0@1 1 1@-1 1 1@1-1 1@1-1 1@1 1 1)]